【发布时间】:2021-06-10 03:40:39
【问题描述】:
所以,我是 PHP 新手,主要问题是我正在学习和听课,我完全按照讲师所做的那样做,但我得到了不同的结果,在我展示我的代码之前,这是我的项目目录:
这是我的代码:教练说如果我们将 action = "" 留空,表格会被当前文件处理,这就是我想要做的。
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>PHP Form</title>
</head>
<body>
<h1>PHP Forms</h1>
<form action="get" method="" name="">
<label>Username:</label>
<input type = "text" name = "txtUsername" value = ""/>
<br/><br/>
<label>Email:</label>
<input type = "text" name = "txtUserEmail" value = ""/>
<br/><br/>
<label>List:</label>
<select name = "selMember">
<option value = "Please select">Please select</option>
<option value = "Joey">Joey</option>
<option value = "Rachel">Rachel</option>
<option value = "Chandler">Chandler</option>
<option value = "Monica">Monica</option>
<option value = "Phoebe">Phoebe</option>
<option value = "Ross">Ross</option>
</select>
<br/><br/>
<input type = "submit" value = "Submit" name = "subForm" />
</form>
<h2>User submitted data:</h2>
<?php
$username = $_GET['txtUsername'];
$userEmail = $_GET['txtUserEmail'];
$selectedMember = $_GET['selMember'];
echo "Username: $username <br/>";
echo "User's email: $userEmail <br/>";
echo "User's selected member: $selectedMember <br/>";
?>
</body>
</html>
所以这是表格:请忽略警告通知,因为教练说他将在下一个视频中教如何处理它。
问题是表单被提交到这个 URL: "http://localhost:8080/php_code/get?txtUsername=anyone123&txtUserEmail=anyone%40gmail.com&selMember=Rachel&subForm=Submit"
URL 应该提交到“http://localhost:8080/php_code/phpForms.php...”而不是“http://localhost:8080/php_code/...”。
所以,如果我手动输入正确的 URL: "http://localhost:8080/php_code/phpForms.php/get?txtUsername=anyone123&txtUserEmail=anyone%40gmail.com&selMember=Rachel&subForm=Submit", 表单提交的工作方式与讲师一样:
那么,我该如何解决这个问题呢?我是否将文件放在错误的目录中?
【问题讨论】:
-
表单方法应该是get/post,动作应该是""。你在做相反的事情。
标签: php html forms visual-studio-code xampp