【发布时间】:2021-05-08 07:41:43
【问题描述】:
React.js 版本:v16.8.2
在功能组件中使用 Context 结合 useReducer,当我更改某些状态时,导致所有由 'Context.Provider' 包裹的子组件被重新渲染。我应该怎么做才能防止对这些子组件进行一些不必要的重新渲染?
现在,我使用 'useMemo' 来包装所有子组件的 DOM 结构。
但是关于这种方式,我想知道它是否有优化性能的效果?因为这样只会导致DOM结构被缓存,但它自己的功能组件还是会被重新执行。
同时我也想知道我使用的'useMemo'缓存的DOM结构是否会再次执行diff算法逻辑?
这是我的代码。
- 根组件:
import React, { useReducer } from 'react'
import * as styles from './home.scss'
import { Context } from './context.js'
import Component1 from './component1'
import Component2 from './component2'
import Component3 from './component3'
const Main = () => {
const initState = {
count: 0
}
const reducer = (state, action) => {
switch (action.type) {
case 'add':
return {
...state,
count: action.payload.count
}
default:
return state
}
}
const [state, dispatch] = useReducer(reducer, initState)
return (
<Context.Provider value={{ state, dispatch }}>
<div className={styles.wrapper}>
<Component1 />
<Component2 />
<Component3 />
</div>
</Context.Provider>
)
}
export default Main
- 子组件之一
import React, { useContext, useCallback, useMemo } from 'react'
import * as styles from '../home.scss'
import { Context } from '../context.js'
const Component2 = () => {
console.log(2)
const { state, dispatch } = useContext(Context)
const addClick = useCallback(() => {
dispatch({
type: 'add',
payload: {
count: 3
}
})
}, [])
return (
useMemo(() => {
return (
<div className={styles.component2}>
{console.log(2 + '!')}
<button onClick={addClick}>add</button>
<div>{state.count}</div>
</div>
)
}, [addClick, state.count])
)
}
export default Component2
- 上下文
import React from 'react'
export const Context = React.createContext({
dispatch: () => {},
state: {}
})
【问题讨论】:
标签: javascript reactjs diff memo