【发布时间】:2011-09-14 22:03:08
【问题描述】:
我目前正在尝试制作一条跟随鼠标的彩虹轨迹。我使用 Linkedlist 来绘制鼠标的点,以便跟踪。小径本身看起来很完美,只是小径中的颜色看起来不正确。我希望他们彼此淡入。有人告诉我使用线性插值,经过一段时间的研究,它似乎可以工作,我只是不知道如何实现它。
这是我目前的代码:
import impsoft.bots.ColorBot;
import impsoft.scripting.ibot.interfaces.AutoPaint;
import impsoft.scripting.types.ColorScript;
import java.awt.BasicStroke;
import java.awt.Color;
import java.awt.Graphics;
import java.awt.Graphics2D;
import java.awt.RenderingHints;
import java.util.Deque;
import java.util.LinkedList;
import impsoft.scripting.ibot.structs.XY;
import impsoft.scripting.types.ColorSkeltonScriptable;
import impsoft.scripting.types.parallel.scriptjobs.ScriptJob;
public class MouseTrail extends ColorScript implements AutoPaint {
public MouseTrail(ColorBot c) {
super(c);
}
public void script() throws InterruptedException {
while(true) {
mt.setSize(500);
mt.exec();
sleep(100);
}
}
public static String name = "Mouse trail test";
public static String author = "Llaver";
public static String description = "test for mouse trail";
public static double version = 1.00;
public class MouseTrail2 extends ScriptJob implements AutoPaint {
private int size;
private final ColorSkeltonScriptable cs;
private final Deque<XY> trail = new LinkedList<XY>();
private final Color[] rainbow = new Color[]{
Color.RED, Color.YELLOW, Color.GREEN, Color.CYAN, Color.BLUE, Color.magenta
};
public MouseTrail2(ColorSkeltonScriptable cs) {
super(cs);
this.cs = cs;
}
public void setSize(int s) {
size = s;
s = 200;
}
public void runV() {
try {
while (true) {
synchronized (trail) {
if (trail.size() >= size) {
trail.pop();
}
trail.offer(cs.getCurrentMouseXY());
}
sleep(1);
}
} catch (InterruptedException e) {
}
}
@Override
public void paint(Graphics g) {
final Graphics2D g2d = (Graphics2D) g;
g2d.setStroke(new BasicStroke(3, BasicStroke.CAP_BUTT, BasicStroke.JOIN_ROUND));
g2d.setRenderingHint(RenderingHints.KEY_ANTIALIASING, RenderingHints.VALUE_ANTIALIAS_ON);
synchronized (trail) {
float perc;
int idx;
for(int i = 1 ; i < trail.size() - 1 ; i++){
XY current = ((LinkedList<XY>) trail).get(i);
XY next = ((LinkedList<XY>) trail).get(i - 1);
perc = ((float)i / trail.size()) * 100f;
idx = Math.round((perc * (float)rainbow.length) / 100f);
if(idx >= rainbow.length)idx -= 1;
g2d.setColor(rainbow[idx]);
g.drawLine(current.x, current.y, next.x, next.y);
}
}
}
}
@Override
public void paint(Graphics arg0) {
}
private MouseTrail2 mt = new MouseTrail2(this);
}
一些图片:
这是我现在拥有的:
http://img11.imageshack.us/img11/3031/mousetrailhavenow.png
这就是我想要得到的:
http://img594.imageshack.us/img594/7381/mousetrailtryingtoget.png
这可能会让这更清楚一点吗?
【问题讨论】:
-
当我尝试路径颜色取决于它在屏幕上的位置而不是它在后面的路径中的位置时。我需要它,以便它可以从 LinkedList 中获取积分并以此为基础。如果这有意义的话
-
你可以使用什么here?
-
不多=/我已经尝试过lineargradientpaint,但它也不起作用。它制作一个盒子而不是跟随指定的点
-
我添加了一些图片来展示我正在尝试做的事情,如果这样可以让事情更清晰一些
-
为什么不更新您的问题或使用修改后的代码添加答案?
标签: java linked-list gradient linear-interpolation