使用意图在活动之间传递数据

Question

我正在尝试在活动之间传递数据

我使用意图在常规活动之间传递数据

考虑下面的代码::

AndroidTabRestaurantDescSearchListView.java

public class AndroidTabRestaurantDescSearchListView extends TabActivity {

    // TabSpec Names
    private static final String INBOX_SPEC = "Rating";
    private static final String OUTBOX_SPEC = "Price";

    Button Photos;
    Button Filter;
    Button Search;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);

        TabHost tabHost = getTabHost();

        // Inbox Tab
        TabSpec inboxSpec = tabHost.newTabSpec(INBOX_SPEC);
        Intent inboxIntent = new Intent(this, RatingDescriptionSearchActivity.class);
        inboxSpec.setIndicator(INBOX_SPEC);
        // Tab Content
        inboxSpec.setContent(inboxIntent);

        // Outbox Tab
        TabSpec PriceSpec = tabHost.newTabSpec(OUTBOX_SPEC);
        Intent PriceIntent = new Intent(this, PriceDescriptionSearchActivity.class);
        PriceSpec .setIndicator(OUTBOX_SPEC);
        PriceSpec.setContent(PriceIntent);


        // Adding all TabSpec to TabHost
        tabHost.addTab(inboxSpec); 
        tabHost.addTab(PriceSpec); 

        //Set the current value tab to default first tab
        tabHost.setCurrentTab(0);

    }

}

---

假设我将来自名为Activity-1 的其他活动的数据作为意图发送到AndroidTabRestaurantDescSearchListView

现在我如何才能接收从Activity-1 获得的AndroidTabRestaurantDescSearchListView 中的数据，然后再次将其传递给RatingDescriptionSearchActivity

图形表示是 ::

{EDIT} -- 如果这可能基于答案 --- 歧义，因为 AndroidTabRestaurantDescSearchListView 是一个选项卡活动

TabSpec inboxSpec = tabHost.newTabSpec(INBOX_SPEC);
        Intent inboxIntent = new Intent(this, RatingDescriptionActivity.class);
        intent.putExtra("keyName", value);
        inboxSpec.setIndicator(INBOX_SPEC);
        // Tab Content
        inboxSpec.setContent(inboxIntent);

Answer 1

将数据从Activity-1 传递到AndroidTabRes..，如下所示：

在发送活动时...

Intent intent = new Intent(current.this, AndroidTabRestaurantDescSearchListView.class);
intent.putExtra("keyName","value");
startActivity(intent);

在AndroidTabRes..活动...

  String data = getIntent().getExtras().getString("keyName");

因此，您可以在从发送活动接收活动时获得数据...

在你的 AndroidTabRestaurantDescSearchListView 课堂上，这样做：

String value= getIntent().getStringExtra("keyName");

Intent intent = new Intent(this, RatingDescriptionSearchActivity.class);
intent.putExtra("keyName", value);
startActivity(intent);

然后在您的 RatingDescriptionSearchActivity 班级中，执行以下操作：

 String data= getIntent().getStringExtra("keyName");

Answer 2

在您的 AndroidTabRestaurantDescSearchListView 活动中尝试此操作

Intent intent  = new Intent(this,RatingDescriptionSearchActivity.class );
intent.putExtras( getIntent().getExtras() );
startActivity( intent );  

然后从RatingDescriptionSearchActivity活动中调用

getIntent().getStringExtra("key")

Answer 3

你可以使用Bundle来获取数据：

Bundle extras = intent.getExtras();
String data = extras.getString("data"); // use your key 

你可以再次将此数据传递给下一个活动：

 Intent intent = new Intent(this, next_Activity.class);
   intent.putExtra("data", data);
   startActivity(intent);

Answer 4

简单。

假设在您的 Activity-1 中，您这样做了：

String stringExtra = "Some string you want to pass";

Intent intent = new Intent(this, AndroidTabRestaurantDescSearchListView.class);

//include the string in your intent
intent.putExtra("string", stringExtra);

startActivity(intent);

在您的 AndroidTabRestaurantDescSearchListView 类中，执行以下操作：

//fetch the string  from the intent
String extraFromAct1 = getIntent().getStringExtra("string");

Intent intent = new Intent(this, RatingDescriptionSearchActivity.class);

//attach same string and send it with the intent
intent.putExtra("string", extraFromAct1);
startActivity(intent);

然后在您的 RatingDescriptionSearchActivity 类中，执行以下操作：

String extraFromAct1 = getIntent().getStringExtra("string");

Answer 5

主要活动

public class MainActivity extends Activity {

    EditText user, password;
    Button login;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        user = (EditText) findViewById(R.id.username_edit);
        password = (EditText) findViewById(R.id.edit_password);
        login = (Button) findViewById(R.id.btnSubmit);
        login.setOnClickListener(new OnClickListener() {
            @Override
            public void onClick(View v) {
                Intent intent = new Intent(MainActivity.this,Second.class);

                String uservalue = user.getText().toString();
                String name_value = password.getText().toString();
                String password_value = password.getText().toString();

                intent.putExtra("username", uservalue);
                intent.putExtra("password", password_value);
                startActivity(intent);
            }
        });
    }
}

第二个活动您要在其中接收数据

public class Second extends Activity{

    EditText name, pass;
    @Override

    protected void onCreate(Bundle savedInstanceState) {

        super.onCreate(savedInstanceState);
        setContentView(R.layout.second_activity);

        name = (EditText) findViewById(R.id.editText1);
        pass = (EditText) findViewById(R.id.editText2);

        String value = getIntent().getStringExtra("username");
        String pass_val = getIntent().getStringExtra("password");
        name.setText(value);
        pass.setText(pass_val);
    }
}

Answer 6

在 FirstActivity 中：

Intent sendDataToSecondActivity = new Intent(FirstActivity.this, SecondActivity.class);
sendDataToSecondActivity.putExtra("USERNAME",userNameEditText.getText().toString());
sendDataToSecondActivity.putExtra("PASSWORD",passwordEditText.getText().toString());
startActivity(sendDataToSecondActivity);

在 SecondActivity

在onCreate()

String userName = getIntent().getStringExtra("USERNAME");
String passWord = getIntent().getStringExtra("PASSWORD");

Answer 7

我喜欢用这个干净的代码只传递一个值：

startActivity(new Intent(context, YourActivity.class).putExtra("key","value"));

这使得代码更易于编写和理解。