【发布时间】:2017-09-26 06:16:23
【问题描述】:
如何使用 json 数据在谷歌地图中制作多个标记。 我试过用单个标记它正在工作 但没有多个标记。
这是单个标记的代码(它正在工作)
var lat=position.coords.latitude;
var lang=position.coords.longitude;
var myLatlng = new google.maps.LatLng(lat,lang);
var myMapOptions = {
zoom: 12
,center: myLatlng
,mapTypeId: google.maps.MapTypeId.HYBRID
};
var theMap = new google.maps.Map(document.getElementById("map_canvas"), myMapOptions);
var image = "images/tag.png"; //IMAGE TAG
var marker = new google.maps.Marker({
map: theMap,
draggable: false,
position: new google.maps.LatLng(lat,lang),
visible: true,
icon: image,
title:restaurantName // Title
});
var myOptions = {
content: ""
,disableAutoPan: false
,maxWidth: 0
,pixelOffset: new google.maps.Size(-140, -110)
,pixelOffset: new google.maps.Size(140, 110)
,zIndex: null
,boxStyle: {
background: "url('tipbox.gif') no-repeat"
,opacity: 0.90
}
,closeBoxMargin: "10px 2px 2px 2px"
,closeBoxURL: "http://www.google.com/intl/en_us/mapfiles/close.gif"
,infoBoxClearance: new google.maps.Size(1, 1)
,isHidden: false
,pane: "floatPane"
,enableEventPropagation: false
};
这是在标记被点击时进行描述
var contentString = '<div class="map_anotaion_title">Description</div>'; //Address on pin click
var infowindow = new google.maps.InfoWindow({
content: contentString
});
infowindow.open(theMap,marker);
google.maps.event.addListener(marker, "click", function (e) {
infowindow.open(theMap,marker);
});
这是我尝试从 JSON 加载多个标记的代码(它不工作)
var lat=position.coords.latitude;
var lang=position.coords.longitude;
var myLatlng = new google.maps.LatLng(lat,lang);
var myMapOptions = {
zoom: 12
,center: myLatlng
,mapTypeId: google.maps.MapTypeId.HYBRID
};
var theMap = new google.maps.Map(document.getElementById("map_canvas"), myMapOptions);
var image = "images/tag.png";
$.getJSON('http://myweb.com/services/get_loc_komp.php', function(json1) {
$.each(json1, function(key, data) {
var marker = new google.maps.Marker({
map: theMap,
draggable: false,
position: new google.maps.LatLng(data.latd,data.lotd),
visible: true,
icon: image,
title:data.street // Title
});
});
});
var myOptions = {
content: ""
,disableAutoPan: false
,maxWidth: 0
,pixelOffset: new google.maps.Size(-140, -110)
,pixelOffset: new google.maps.Size(140, 110)
,zIndex: null
,boxStyle: {
background: "url('tipbox.gif') no-repeat"
,opacity: 0.90
}
,closeBoxMargin: "10px 2px 2px 2px"
,closeBoxURL: "http://www.google.com/intl/en_us/mapfiles/close.gif"
,infoBoxClearance: new google.maps.Size(1, 1)
,isHidden: false
,pane: "floatPane"
,enableEventPropagation: false
};
var contentString = '<div class="map_anotaion_title">Description</div>'; //Address on pin click
var infowindow = new google.maps.InfoWindow({
content: contentString
});
infowindow.open(theMap,marker);
google.maps.event.addListener(marker, "click", function (e) {
infowindow.open(theMap,marker);
});
请帮帮我
非常感谢
【问题讨论】:
-
你确定这与android标签有关吗?
-
是的。我把这段代码放在android aps中
-
您能否向我们展示一个从 API 端点返回的 JSON 示例?例如。您在
getJSON()回调中从json1获得的样本数据是什么? -
谢谢@Terry,你的简单问题,叫醒我..我在捕获 json 变量时出错了..非常感谢,它现在可以工作了
标签: javascript jquery google-maps