【问题标题】:Extracting JSON data from Google geocoding API in R从 R 中的 Google 地理编码 API 中提取 JSON 数据
【发布时间】:2017-08-10 07:58:22
【问题描述】:

我对 Json 数据结构很陌生,因此无法从中提取数据。

这是来自存储在 csv 文件中的 Json 数据的示例行

row1)   {"results":[{"address_components":[{"long_name":"16","short_name":"16","types":["street_number"]},{"long_name":"Bhagwan Tatyasaheb Kawade Road","short_name":"BT Kawde Road","types":["route"]},{"long_name":"Palmgrove Society","short_name":"Palmgrove Society","types":["neighborhood","political"]},{"long_name":"Uday Baug","short_name":"Uday Baug","types":["political","sublocality","sublocality_level_2"]},{"long_name":"Ghorpadi","short_name":"Ghorpadi","types":["political","sublocality","sublocality_level_1"]},{"long_name":"Pune","short_name":"Pune","types":["locality","political"]},{"long_name":"Pune","short_name":"Pune","types":["administrative_area_level_2","political"]},{"long_name":"Maharashtra","short_name":"MH","types":["administrative_area_level_1","political"]},{"long_name":"India","short_name":"IN","types":["country","political"]},{"long_name":"411001","short_name":"411001","types":["postal_code"]}],"formatted_address":"16, BT Kawade Road, Palmgrove Society, Uday Baug, 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row2) {"results":[{"address_components":[{"long_name":"Canal Road","short_name":"Canal Rd","types":["route"]},{"long_name":"Empress Garden View Society","short_name":"Empress Garden View Society","types":["political","sublocality","sublocality_level_3"]},{"long_name":"Uday Baug","short_name":"Uday Baug","types":["political","sublocality","sublocality_level_2"]},{"long_name":"Ghorpadi","short_name":"Ghorpadi","types":["political","sublocality","sublocality_level_1"]},{"long_name":"Pune","short_name":"Pune","types":["locality","political"]},{"long_name":"Pune","short_name":"Pune","types":["administrative_area_level_2","political"]},{"long_name":"Maharashtra","short_name":"MH","types":["administrative_area_level_1","political"]},{"long_name":"India","short_name":"IN","types":["country","political"]},{"long_name":"411001","short_name":"411001","types":["postal_code"]}],"formatted_address":"Canal Rd, Empress Garden View Society, Uday Baug, Ghorpadi, Pune, Maharashtra 411001, 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row3) {"results":[{"address_components":[{"long_name":"Canal Road","short_name":"Canal Rd","types":["route"]},{"long_name":"Empress Garden View Society","short_name":"Empress Garden View Society","types":["political","sublocality","sublocality_level_3"]},{"long_name":"Uday Baug","short_name":"Uday Baug","types":["political","sublocality","sublocality_level_2"]},{"long_name":"Ghorpadi","short_name":"Ghorpadi","types":["political","sublocality","sublocality_level_1"]},{"long_name":"Pune","short_name":"Pune","types":["locality","political"]},{"long_name":"Pune","short_name":"Pune","types":["administrative_area_level_2","political"]},{"long_name":"Maharashtra","short_name":"MH","types":["administrative_area_level_1","political"]},{"long_name":"India","short_name":"IN","types":["country","political"]},{"long_name":"411001","short_name":"411001","types":["postal_code"]}],"formatted_address":"Canal Rd, Empress Garden View Society, Uday Baug, Ghorpadi, Pune, Maharashtra 411001, 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我正在尝试从第一次出现的地址组件中提取值

这样我的虚拟代码看起来像

我正在检查这些字符向量

 chck_list=c("street_address","street_number","route","intersection","political","country","administrative_area_level_1","administrative_area_level_2","administrative_area_level_3","administrative_area_level_4","administrative_area_level_5","colloquial_area","locality","ward","sublocality","neighborhood","premise","subpremise","postal_code","natural_feature","airport","park","point_of_interest")

这是试用码

 js <- fromJSON(as.character(json_data_df1[1:nrow(json_data_df1), 'Json_obj']))
    count_numb=list()
    Type=list()
    long_name=list()
    short_name=list()

    for(i in 1:nrows(js)){
    if(js$status=="ok"){
    count_numb[i] <- length(js[1:nrows(js)][grep("type",js$results[[1]]$address_components[[1]])]) #Counting number of times the word "type" occurs so that the loop can be iterated that many number of times.
    if(js$results[[1]]$address_components[[1]] %in% chck_list) {
    Type[i] = #print the word from the object chck_list that is present in data
    long_name[i] = #print the value of long_name from the data that corresponds to Type[i]
    short_name[i] = #print the value of short_name from the data that corresponds to Type[i]
    }
}

所以我的 o/p 看起来像

      Street_number  route                                neighborhood          sublocality_level_2     sublocality_level_1    Locality     Sub_locality_level_3             ....
1)      16            Bhagwan Tatyasaheb Kawade Road       Palmgrove Society     Uday Baug               Ghorpadi               Pune           NA                             ....
2)      NA            Canal Road                           NA                    Uday Baug               Ghorpadi               Pune         Empress Garden View Society                        
.       .                .
.       .                . 
.       .                .

P.S= json_data_df1 是我的数据框的名称;; Json_obj 是 Json 对象所在列的名称

有没有人知道我该怎么做。

任何帮助将不胜感激。

谢谢。

【问题讨论】:

    标签: json r google-geocoding-api rjson rjsonio


    【解决方案1】:

    我认为您必须首先在 fromJSON 函数中使用 simplifyDataFrame = FALSE 才能将数据作为列表获取:

    dat = jsonlite::fromJSON("your_example_data.json", simplifyDataFrame = FALSE)
    

    然后使用嵌套的 lapply 接收每个子列表的三个项目(我修改 lapply() 函数考虑到您的最后评论),

    res = lapply(dat, function(x) {
    
      lapply(x[["results"]], function(y) {
    
        do.call(rbind, lapply(y[['address_components']], function(z) {
    
          if (is.null(z)) {                            # if array is empty return NA's for all 3 output items
    
            c(rep(NA, 3))}
    
          else {
    
            tmp_array_type = z[['types']]               # temporarily get the json-array including "street_number", "route", "neighborhood" etc.
    
            if (length(tmp_array_type) == 0) {          # if array is of length 0 then return NA
    
              out_type = NA}
    
            else if (length(tmp_array_type) == 3) {     # it array is of length 3 return the 3rd item
    
              out_type = z[['types']][3]}
    
            else if (("political" %in% tmp_array_type) && length(tmp_array_type) > 1) {    # if array includes political and it's length is greater than 1 then remove political and then receive the 1st item
    
              tmp_array_type = tmp_array_type[-which(tmp_array_type == "political")]
    
              out_type = tmp_array_type[1]}
    
            else {
    
              out_type = tmp_array_type[1]                 # for all other cases return the 1st item of the array
            }
    
            c(out_type, z[['long_name']], z[['short_name']])
          }
        }))
      })
    })
    

    示例输出

    [[1]]
    [[1]][[1]]
          [,1]                          [,2]                             [,3]               
     [1,] "street_number"               "16"                             "16"               
     [2,] "route"                       "Bhagwan Tatyasaheb Kawade Road" "BT Kawde Road"    
     [3,] "neighborhood"                "Palmgrove Society"              "Palmgrove Society"
     [4,] "sublocality_level_2"         "Uday Baug"                      "Uday Baug"        
     [5,] "sublocality_level_1"         "Ghorpadi"                       "Ghorpadi"         
     [6,] "locality"                    "Pune"                           "Pune"             
     [7,] "administrative_area_level_2" "Pune"                           "Pune"             
     [8,] "administrative_area_level_1" "Maharashtra"                    "MH"               
     [9,] "country"                     "India"                          "IN"               
    [10,] "postal_code"                 "411001"                         "411001"           
    
    [[1]][[2]]
         [,1]                          [,2]              [,3]             
    [1,] "sublocality_level_2"         "Jambhulkar Mala" "Jambhulkar Mala"
    [2,] "sublocality_level_1"         "Wanowrie"        "Wanowrie"       
    [3,] "locality"                    "Pune"            "Pune"           
    [4,] "administrative_area_level_2" "Pune"            "Pune"           
    [5,] "administrative_area_level_1" "Maharashtra"     "MH"             
    [6,] "country"                
    
    .....
    

    如果您想修改 lapply() 函数或 ifelse 语句,那么可以在 here 找到一个很好的教程。

    【讨论】:

    • 哦,这很好,但我认为您错过了我输出中预期的“类型”列...
    • 我编辑了答案以说明“类型”列。
    • 我将 JSON 内容存储在 csv 文件中。我在 R 中导入并将该对象命名为“json_data_df”。所以在运行第一行代码后,即“dat = jsonlite::fromJSON("json_data_df", simpleDataFrame = FALSE)”给了我错误“错误:参数'txt'必须是一个JSON字符串、URL或文件。”。所以我将其更改为字符“dat = jsonlite::fromJSON(as.character(json_data_df), simpleDataFrame = FALSE)”。但它仍然给出错误“错误:词法错误:json文本中的无效字符。c(“{\”results\“:[{\”add​​ress_com(就在这里)------^“
    • jsonlite::fromJSON() 函数要求输入是字符串、url 或文件。我建议使用 .csv 文件的路径作为函数的输入,例如 jsonlite::fromJSON("your_example_file.csv")。但是,我认为您的输入文件是 .json 类型的。
    • 在使用此语句后仍然给我错误 "dat = jsonlite::fromJSON("C:/Users/JSON Sample.csv", simpleDataFrame = FALSE)" "Error in parse_con(txt, bigint_as_char ) : 解析错误: 尾随垃圾 "{"​​"results"":[{""address_components"":[{" (就在这里) ------^" .... 这个 csv 文件包含一个单列每行此类 JSON 对象的列表并且它没有列名,这会影响吗?
    【解决方案2】:

    有一些可用的地理编码包可以让您的生活更轻松,例如我的 googleway 包,它可以查询各种 Google API 并将结果“简化”到 data.frames/lists 中。从那里您可以使用标准的 list/data.frame 子集方法提取所需的元素。

    library(googleway)
    
    addresses <- c("Bhagwan Tatyasaheb Kawade Road", "Empress Garden View Society")
    apiKey <- 'your_api_key'
    
    lst_geocode <- lapply(addresses, function(x){
        google_geocode(address = x,
                                     key = apiKey)
    })
    
    lapply(lst_geocode, function(x){
        x[['results']][['address_components']]
    })
    
    # [[1]]
    # [[1]][[1]]
    # long_name    short_name                                  types
    # 1 Bhagwan Tatyasaheb Kawade Road BT Kawde Road                                  route
    # 2                           Pune          Pune                    locality, political
    # 3                           Pune          Pune administrative_area_level_2, political
    # 4                    Maharashtra            MH administrative_area_level_1, political
    # 5                          India            IN                     country, political
    # 
    # 
    # [[2]]
    # [[2]][[1]]
    # long_name         short_name                                       types
    # 1    Sopan Baug Road      Sopan Baug Rd                                       route
    # 2 Sopan Baug Society Sopan Baug Society political, sublocality, sublocality_level_3
    # 3        Kavade Mala        Kavade Mala political, sublocality, sublocality_level_2
    # 4           Ghorpadi           Ghorpadi political, sublocality, sublocality_level_1
    # 5               Pune               Pune                         locality, political
    # 6               Pune               Pune      administrative_area_level_2, political
    # 7        Maharashtra                 MH      administrative_area_level_1, political
    # 8              India                 IN                          country, political
    # 9             411001             411001                                 postal_code
    

    【讨论】:

    • 这里的“apiKey”是什么意思?地址是我的 json 数据吗?
    • @deepesh - 使用您需要的任何 Google API an API key。根据ggmap 库中的geocode 函数,有一些方法可以避免使用它,但Google 指定您需要有一个才能使用他们的服务。
    • @deepesh - 很抱歉,我不明白你评论的第二部分
    • @SymbolixAU- 我作为输入获得的 JSON 数据是 .csv 格式或 .json 格式..所以我认为我不应该考虑 api_key。我只是在 R 中读取 csv 文件或 .json 文件,并尝试以给定的方式从中提取数据。我的第二个问题是,对象“地址”到底是什么,是 json 数据还是其他什么?
    • 是的,你的方法是提取数据的好方法,“googleway”+1。但是任何关于如何解决我的问题的建议,以便我获得所需的输出格式。
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