导航菜单 PHP ECHO INSIDE ECHO

Question

我正在制作我的导航菜单，我想添加一个活动类 这是我的代码

我想输出 CSTYLE 并使用 'if 来回显活动类

<?php
$result = mysql_query("SELECT CSTYLE,id, name, DESCRIPTION FROM menu where VISIBLE='1'   
ORDER BY `order` ASC") or die(mysql_error());               
while($row = mysql_fetch_array($result)){
printf('<li %s id="page_%s">%s %s </a></li> ', $row['CSTYLE'], $row['id'],  
$row['name'],$row['DESCRIPTION']);
}
?>

这是CSTYLE的内容

if ($thisPage=="HOME")  echo " class=\"active\""

Answer 1

请尝试以下代码

  <?php
         $result = mysql_query("SELECT CSTYLE,id, name, DESCRIPTION FROM menu where VISIBLE='1'   
        ORDER BY `order` ASC") or die(mysql_error());               
        while($row = mysql_fetch_array($result)){
            if (strtolower($thisPage)==strtolower($row[2])) {
                printf('<li class="active" %s id="page_%s">%s %s </a></li> ', $row['CSTYLE'], $row['id'],  
            $row['name'],$row['DESCRIPTION']);
            }
            else
           {
                printf('<li %s id="page_%s">%s %s </a></li> ', $row['CSTYLE'], $row['id'],  
            $row['name'],$row['DESCRIPTION']);
           } 

    }
    ?>