【发布时间】:2021-07-22 12:11:32
【问题描述】:
我正在学习 kotlin DSL,特别是 Teamcity,我看到了一个我还不太了解的初始化模式
这里是代码
package org.arhan.kotlin
fun main() {
val project = project {
configuration {
step {
name = "step 1"
command = "hi"
}
customstep {
name = "flang"
anotherCommand = "derp"
command = "1111"
}
}
}
println(project.configurations[0].steps[1].command)
}
fun project(block: Project.() -> Unit): Project {
return Project().apply(block)
}
fun Project.configuration(block: Configuration.() -> Unit): Configuration {
val configuration = Configuration().apply(block)
configurations.add(configuration)
return configuration
}
fun Configuration.step(block: Step.() -> Unit): Step {
val step = Step().apply(block)
steps.add(step)
return step
}
class Project {
var configurations = mutableListOf<Configuration>()
fun build(block: Configuration.() -> Unit) = Configuration().apply(block)
}
class Configuration {
var steps = mutableListOf<Step>()
}
open class Step {
final lateinit var name: String
var command: String = ""
}
open class CustomStep(): Step(){
var anotherCommand: String = ""
constructor(init: CustomStep.() -> Unit): this(){
// what does this do?
init()
}
}
fun Configuration.customstep(block: CustomStep.() -> Unit): Step {
// how is this constructor initialized
val step = CustomStep(block)
steps.add(step)
return step
}
具体问题是关于CustomStep 类是如何初始化的。它包含一个带有 CustomStep as the reciever 的 lambda(这是正确的术语吗?)。
然后我在构造函数中调用init(),它根据传入的块初始化新创建的CustomStep。
我不确定初始化是如何工作的。或者更确切地说,这里使用了哪种特定的 Kotlin 语言功能。
如果我改用以下方式编写,这有什么不同?
open class CustomStep(): Step(){
var anotherCommand: String = ""
// no constructor
}
fun Configuration.customstep(block: CustomStep.() -> Unit): Step {
// use apply vs. passing in the block
val step = CustomStep().apply(block)
steps.add(step)
return step
}
谢谢
【问题讨论】:
-
我相信这是type-safe builder的实现。
标签: kotlin kotlin-dsl