【发布时间】:2019-01-30 10:06:03
【问题描述】:
在这个程序中,我有三个活动主要、第二和第三。当应用程序打开时,会有一个空白的文本视图和按钮。选择该按钮将带您进入第二个活动,用户可以在其中输入姓名、电话号码和电子邮件地址。填写完这些表单后,用户将点击一个按钮来存储该信息并将它们带回主要活动。当回到主要活动时,用户将看到他们输入的名称显示在曾经空白的文本视图中。然后他们可以选择那个文本视图,这会将他们带到第三个活动,显示他们在第二个活动中输入的姓名、电话号码和电子邮件地址。
除了将数据从第二个活动传递到第三个活动之外,我一切正常。我做了一些研究,发现捆绑包和共享首选项可以做很多事情。我对它们不太熟悉,因为这对我来说很新。我确实尝试过实施它们,但没有任何运气。无论如何,代码如下,任何帮助、反馈或指导将不胜感激。先感谢您!
主要活动:
public class MainActivity extends AppCompatActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
}
public void onClick(View view){
startActivityForResult(new Intent(getApplicationContext(),SecondActivity.class),999);
}
public void onClickText(View v)
{
startActivityForResult(new Intent(getApplicationContext(),ThirdActivity.class),999);
}
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if(requestCode == 999 && resultCode == RESULT_OK)
{ TextView contactView = (TextView) findViewById(R.id.contactDisplay);
contactView.setText(data.getStringExtra("Name"));
}
}}
第二个活动:
public class SecondActivity extends AppCompatActivity {
public String textName;
public String emailAddress;
public int phoneNumber;
private TextView textNameView2;
EditText textPersonName;
EditText number;
EditText textEmailAddress;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_second);
}
public void onClickTwo(View view)
{
textPersonName = (EditText) findViewById(R.id.name);
number = (EditText) findViewById(R.id.number);
textEmailAddress = (EditText) findViewById(R.id.email);
textName = textPersonName.getText().toString();
emailAddress = textEmailAddress.getText().toString();
phoneNumber = Integer.valueOf(number.getText().toString());
showToast(textName +"added");
Intent backMain = new Intent(this, MainActivity.class);
// Intent backMain = new Intent();
backMain.putExtra("Name",textName);
// backMain.putExtra("Email", emailAddress);
// backMain.putExtra("Phone", phoneNumber);
setResult(RESULT_OK, backMain);
Intent thirdMain = new Intent(this, ThirdActivity.class);
thirdMain.putExtra("Name",textName);
thirdMain.putExtra("Email",emailAddress);
thirdMain.putExtra("Phone",phoneNumber);
setResult(RESULT_OK,thirdMain);
finish();
}
private void showToast(String text)
{
Toast.makeText(this,text, Toast.LENGTH_LONG).show();
}}
第三个活动:
public class ThirdActivity extends AppCompatActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_third);
}
protected void onActivityResult(int requestCode, int resultCode, Intent data){
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == 999 && resultCode == RESULT_OK) {
TextView contact = (TextView) findViewById(R.id.contactNameView);
contact.setText(data.getStringExtra("Name"));
TextView phone = (TextView) findViewById(R.id.phoneView);
phone.setText(data.getStringExtra("Phone"));
TextView email = (TextView) findViewById(R.id.emailView);
email.setText(data.getStringExtra("Email"));
}
}
}
【问题讨论】:
-
你给了一个 onclick 函数有两个意图尝试添加单独的按钮移动到第三个活动
标签: java android android-activity textview user-input