根据android的顺序排列数组？

Question

我有一个网络服务，当我调用网络服务时我得到了这个响应。

[
    {
        "ProjectID": 1,
        "SLNO": 1,
        "ID": 1,
        "Type": "Text",
        "Name": "First Name",
        "**Order**": 1,
        "Flag": "F"
    },
    {
        "ProjectID": 1,
        "SLNO": 3,
        "ID": 2,
        "Type": "Text",
        "Name": "Company",
        "**Order**": 5,
        "Flag": "F"
    },
    {
        "ProjectID": 1,
        "SLNO": 4,
        "ID": 4,
        "Type": "Text",
        "Name": "Personal Email",
        "**Order**": 3,
        "Flag": "F"
    },
    {
        "ProjectID": 1,
        "SLNO": 2,
        "ID": 8,
        "Type": "Text",
        "Name": "Last Name",
        "**Order**": 2,
        "Flag": "F"
    }
]

现在我想根据我在这个数组中的顺序对这个完整的数组进行排序？我怎样才能做到这一点？

Answer 1

array = JSONUtil.sort(array, new Comparator(){
               public int compare(Object a, Object b){
                  JSONObject    ja = (JSONObject)a;
                  JSONObject    jb = (JSONObject)b;
                  return Integer.valueOf(ja.getString("**Order**")).compareTo(Integer.valueOf(jb.getString("**Order**")));
               }
            });

Answer 2

首先，将这些数据添加到 ArrayList 或 HashMap 等列表中。然后使用以下代码按顺序对列表数据进行排序。

class HashMapComparator implements Comparator<HashMap<String, String>> {
        private final String key;

        public HashMapComparator(String key) {
            this.key = key;
        }

        @Override
        public int compare(HashMap<String, String> lhs,
                HashMap<String, String> rhs) {
            String firstValue = lhs.get(key);
            String secondValue = rhs.get(key);
            return firstValue.compareTo(secondValue);
        }
    }

并将其称为：

 Collections.sort(yourlistDTO, new HashMapComparator("order"));