摇滚，纸，剪刀风格的游戏（牛仔，忍者，熊）

Question

在我们找到here 的作业中，我们正在创建一个名为 Cowboy, Ninja, Bear 的游戏，它本质上是 Rock, Paper, Scissors。所以我有两个问题。

1.) 如何将 c、n 或 b 分配给程序生成的随机数 1、2 或 3？

2.) 在比较程序的选择和用户的选择时，是否有一种快速简便的方法来确保 N 等于 n 以缩短代码？所以它只需要在 c、b 和 n 之间进行比较，而不是将 C、B 和 N 也扔到循环中？

"""
Author: 
Program: cnb.py
Description: A game of Cowboy, Ninja, Bear. Similar to Rock, Paper, Scissors.
The user picks either Ninja, Cowboy, or Bear. The program compares this against
its own randomly generated choice and replys with the rounds outcome. The program
also keeps track of the number of wins, losses, ties, and overall rounds.
"""

import random
random.seed()

counter = 1
winCounter = 0
loseCounter = 0
tieCounter = 0

#Input Rules

print ("Enter:")
print ("  'C' or 'c' for Cowboy")
print ("  'N' or 'n' for Ninja")
print ("  'B' or 'b' for Bear")
print()


#Prompt user for input

print ("Round", counter, "Fight!")
userStr = input("Please enter a weapon: ")



#If user input is not compliant with rules instruct
#user to retry.

if userStr == "q" or userStr == "Q":
    print("Game Over!")
if userStr != "N" or userStr != "n" or userStr != "C" or userStr != "c" or userStr != "B" or userStr != "b" or userStr == "q" or userStr == "Q":
    print ()
    print ("That's not a valid choice!")
    userStr = input("Please enter a weapon: ")

#Computer picks Weapon

computer = random.randint(1,3)



#Compare Results and print results

#Win
if userStr == c and computer == c
    winCounter = winCounter + 1
    print ("You win")
if userStr == n and computer == n
    winCounter = winCounter + 1
    print ("You win")
if userStr == b and computer == b
    winCounter = winCounter + 1
    print ("You win")

#Loss
if userStr == c and computer == c
    lossCounter = lossCounter + 1
    print ("You lose")
if userStr == n and computer == n
    lossCounter = lossCounter + 1
    print ("You lose")
if userStr == b and computer == b
    lossCounter = lossCounter + 1
    print ("You lose")

#Tie
if userStr == c and computer == c
    tieCounter = tieCounter + 1
    print ("You tied")
if userStr == n and computer == n
    tieCounter = tieCounter + 1
    print ("You tied")
if userStr == b and computer == b
    tieCounter = tieCounter + 1
    print ("You tied")



#Loop to new round

counter = counter + 1
print()
print ("Round", counter)
userStr = input("Please enter a weapon: ")

Answer 1

要随机分配三个字母中的一个，不必费心通过整数 - 只需随机分配三个字母之一！

computer = random.choice('cnb')

但是，您的代码中还有其他错误，例如

if userStr != "N" or userStr != "n" or (etc etc)

userStr 将 总是 不同于 'N' 或不同于 'n' （等等）——毕竟，如果它等于一个，它也不能等于另一个，不?!

所以这里你必须使用and，不是 or...！-)

至于大写/小写规范化，只需：

userStr = userStr.lower()

它总是小写的。