C# 使用正则表达式提取单词

Question

我找到了很多关于如何使用正则表达式检查内容或如何使用正则表达式拆分文本的示例。

但是如何从字符串中提取单词呢？

例子：

aaaa 12312 <asdad> 12334 </asdad>

假设我有这样的东西，我想提取所有数字 [0-9]* 并将它们放在一个列表中。

或者如果我有 2 种不同的元素：

aaaa 1234 ...... 1234 ::::: asgsgd

我想choose digits that come after ..... 和words that come after ::::::

我可以在一个正则表达式中提取这些字符串吗？

Answer 1

在一般情况下，您可以使用捕获括号来做到这一点：

string input = "aaaa 1234 ...... 1234 ::::: asgsgd";
string regex = @"\.\.\.\. (\d+) ::::: (\w+)";
Match m = Regex.Match(input, regex);

if (m.Success) {
    int numberAfterDots = int.Parse(m.Groups[1].Value);
    string wordAfterColons = m.Groups[2].Value;
    // ... Do something with these values
}

但是你问的第一部分（提取所有数字）要容易一些：

string input = "aaaa 1234 ...... 1234 ::::: asgsgd";
var numbers = Regex.Matches(input, @"\d+")
                   .Cast<Match>()
                   .Select(m => int.Parse(m.Value))
                   .ToList();

现在numbers 将是一个整数列表。

Answer 2

这是您第一个问题的解决方案：

   class Program
    {
        static void Main(string[] args)
        {
            string data = "aaaa 12312 <asdad> 12334 </asdad>";

            Regex reg = new Regex("[0-9]+");

            foreach (var match in reg.Matches(data))
            {
                Console.WriteLine(match);
            }

            Console.ReadLine();
        }
    }

Answer 3

对于您的具体示例：

    string firstString = "aaaa 12312 <asdad> 12334 </asdad>";
    Regex firstRegex = new Regex(@"(?<Digits>[\d]+)", RegexOptions.ExplicitCapture);
    if (firstRegex.IsMatch(firstString))
    {
        MatchCollection firstMatches = firstRegex.Matches(firstString);
        foreach (Match match in firstMatches)
        {
            Console.WriteLine("Digits: " + match.Groups["Digits"].Value);
        }
    }

    string secondString = "aaaa 1234 ...... 1234 ::::: asgsgd";
    Regex secondRegex = new Regex(@"([\.]+\s(?<Digits>[\d]+))|([\:]+\s(?<Words>[a-zA-Z]+))", RegexOptions.ExplicitCapture);
    if (secondRegex.IsMatch(secondString))
    {
        MatchCollection secondMatches = secondRegex.Matches(secondString);
        foreach (Match match in secondMatches)
        {
            if (match.Groups["Digits"].Success)
            {
                Console.WriteLine("Digits: " + match.Groups["Digits"].Value);
            }
            if (match.Groups["Words"].Success)
            {
                Console.WriteLine("Words: " + match.Groups["Words"].Value);
            }
        }
    }

希望对您有所帮助。输出是：

Digits: 12312
Digits: 12334
Digits: 1234
Words: asgsgd

Answer 4

这样的事情会做得很好！

var text = "aaaa 12312 <asdad> 12334 </asdad>";
var matches = Regex.Matches(text, @"\w+");

var arrayOfMatched = matches.Cast<Match>().Select(m => m.Value).ToArray();

Console.WriteLine(string.Join(", ", arrayOfMatched));

\w+ 匹配连续的单词字符。然后我们只是从匹配列表中选择值并将它们变成一个数组。

Answer 5

Regex itemsRegex = new Regex(@"(\d*)");
MatchCollection matches = itemsRegex.Matches(text);

int[] values = matches.Cast<Match>().Select(m => Convert.ToInt32(m.Value)).ToArray();

Answer 6

    Regex phoneregex = new Regex("[0-9][0-9][0-9]\-[0-9][0-9][0-9][0-9]");
    String unicornCanneryDirectory = "unicorn cannery 483-8627 cha..."
    String numbersToCall = "";

    //the second argument is where to begin within the match, 
    //we probably want 0, the first character
    Match matchIterator = phoneregex.Match(unicornCanneryDirectory , 0);
    //Success tells us if matchIterator has another match or not
    while( matchIterator.Sucess){
      String aResult = matchIterator.Result();
      //we could manipulate our match now but I'm going to concatenate them all for later
      numbersToCall  += aResult + " ";

      matchIterator = matchIterator.NextMatch();
    }

    // use my concatenated matches now
    String message = "Unicorn rights activists demand more sparkles in the unicorn canneries under the new law...";
    phoneDialer.MassCallWithAutomatedMessage(aResult, message );

http://msdn.microsoft.com/en-us/library/system.text.regularexpressions.match.nextmatch.aspx