Web Api 和 ASP.Net MVC答案

【问题标题】：Web Api and ASP.Net MVCWeb Api 和 ASP.Net MVC
【发布时间】：2016-06-09 13:29:10
【问题描述】：

大家好，我是新来的。我的HomeController 有一个小问题，我将使用 Web API 进行获取和创建，但我无法找到并编写编辑/详细信息和删除。

public class HomeController : Controller
{
    // GET: Home
    public ActionResult Index()
    {

        List<Product1Model> lst =new List<Product1Model>();
        HttpClient Client = new HttpClient();
        Client.BaseAddress = new Uri("http://localhost:19440/");

        Client.DefaultRequestHeaders.Accept.Add(
           new MediaTypeWithQualityHeaderValue("application/json") );
        HttpResponseMessage responsive = Client.GetAsync("api/Product1").Result;
        if (responsive.IsSuccessStatusCode)
        {
            lst = responsive.Content.ReadAsAsync<List<Product1Model>>().Result;
        }
        return View(lst);
    }

    public ActionResult Create()
    {
      return View();
    }

    [HttpPost]
    public ActionResult Create(Product1Model model)
    {
        HttpClient Client = new HttpClient();
        Client.BaseAddress = new Uri("http://localhost:19440/");

        Client.PostAsJsonAsync<Product1Model>("api/Product1",model)
            .ContinueWith((postTask) => postTask.Result.EnsureSuccessStatusCode());
        return RedirectToAction("index");
    }

}

【问题讨论】：

标签： c# asp.net asp.net-mvc asp.net-mvc-4 asp.net-web-api

【解决方案1】：

鉴于示例的当前结构，您只需要冲洗并重复您当前在创建和索引中用于编辑和删除的模式。

假设您遵循约定，

有关详细信息/编辑，您需要在 Views/Home/Detail.cshtml 中创建您的视图，然后添加操作方法来处理 GET 和 POST 请求...

//GET Home/Detail/5
public async Task<ActionResult> Detail(int id) {
    var client = new HttpClient();
    client.BaseAddress = new Uri("http://localhost:19440/");
    client.DefaultRequestHeaders
        .Accept
        .Add(new MediaTypeWithQualityHeaderValue("application/json"));
    string endpoint = string.Format("api/Product1/{0}", id);
    var response= await client.GetAsync(endpoint);
    if (response.IsSuccessStatusCode) {
        var model = response.Content.ReadAsAsync<Product1Model>();
        return View(model);
    }
    return HttpNotFound();
}

//POST Home/Detail/5
[HttpPost]
public async Task<ActionResult> Detail(int id, Product1Model model) {
    HttpClient client = new HttpClient();
    client.BaseAddress = new Uri("http://localhost:19440/");
    string endpoint = string.Format("api/Product1/{0}", id);
    await client.PostAsJsonAsync<Product1Model>(endpoint, model)
        .ContinueWith((postTask) => postTask.Result.EnsureSuccessStatusCode());
    return RedirectToAction("Index");
}

对于删除，它有点棘手，因为您必须从您的视图中决定使用哪种 Http 方法。但是您对 web api 的调用可能需要一个 DELETE 方法。您可以坚持约定并一直使用 HttpDelete，例如...

//DELETE Home/Delete/5
[HttpDelete]
public async Task<ActionResult> Delete(int id) {
    HttpClient client = new HttpClient();
    client.BaseAddress = new Uri("http://localhost:19440/");
    client.DefaultRequestHeaders
        .Accept
        .Add(new MediaTypeWithQualityHeaderValue("application/json"));
    string endpoint = string.Format("api/Product1/{0}", id);
    var responsive = await client.DeleteAsync(endpoint);
    if (responsive.IsSuccessStatusCode) {
        return RedirectToAction("Index");
    }

    return HttpNotFound();
}

您需要确保客户端（View）在发出请求时使用正确的http方法

【讨论】：

【解决方案2】：

public ActionResult Edit(YourModel model)
{
   call your edigint logc
  return View();
}
public ActionResult Details(int itemId)
    {
       YourModel = new ModelType();
        YourModel = Call your Detail Logic

       return view(YourModel  )          
    }

【讨论】：