跳过属性名称，仅使用 json 中的值

Question

我正在尝试使用 NewtonSoft json 4.5 解析为以下 json 字符串：

{
   "Name":"Henrik", 
   "Children":[
   {
      "Name":"Adam",
      "Grandchildren":[
         "Jessica", //How can i only show the value and not the property name?
         "Michael"
      ]
   }
   ]
}

我将序列化为 json 的对象如下所示：

public class Parent
{
   public string Name { get; set; }

   [JsonProperty(PropertyName = "Children")]
   public List<Child> Childs { get; set; }
}

public class Child {
   public string Name { get; set; }

   [JsonProperty(PropertyName = "Grandchildren")]
   public List<GrandChild> GrandChilds { get; set; }
}

public class GrandChild {
   [JsonProperty(PropertyName = "")]
   public string Name { get; set; }
}

我尝试将属性名称设置为空，但它并没有解决问题。

Answer 1

您应该将List<GrandChild> 替换为List<string>，或者像这样为GrandChild 添加一个自定义JsonConverter。

[JsonConverter(typeof(GrandChildConverter))]
public class GrandChild
{
    public string Name { get; set; }
}

public class GrandChildConverter : JsonConverter
{
    public override bool CanConvert(Type objectType)
    {
        return objectType == typeof(GrandChild);
    }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        writer.WriteValue(((GrandChild)value).Name);
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        return new GrandChild { Name = reader.Value.ToString() };
    }
}