【问题标题】:How do i make each movie appear on under their respective date我如何让每部电影出现在各自的日期
【发布时间】:2020-02-26 23:49:16
【问题描述】:

我似乎无法让每部电影都出现在各自的日期下,并且为电影时间选择提供正确的时间下拉菜单

$sql_date = "SELECT DISTINCT sDate, sTitle FROM movieScreenings ";
$result_date = mysqli_query($db, $sql_date);

while($row = mysqli_fetch_array($result_date)) {

    echo "<h2>" . $row['sDate'] . "</h2>";

    $sql_movie = "SELECT * FROM movieList, movieScreenings WHERE title = '" . $row['sTitle'] . "'";
    $result_movie = mysqli_query($db, $sql_movie);

    while($row2 = mysqli_fetch_array($result_movie)) {


        echo "<div class='box'>

              <img class='poster' src='posters/" . $row2['poster'] . "'/>       

              <h2>" . $row2['title'] . "</h2>

              <p>" . $row2['description'] . "</p>";


        $sql_time = "SELECT DISTINCT sTime FROM movieScreenings WHERE sTitle = '" . $row2['title'] . "' AND sDate = '" . $row['sDate'] . "'";
        $result_time = mysqli_query($db, $sql_time);

        while($row3 = mysqli_fetch_array($result_time)) {

            echo "<select name='sTime'>

                  <option value='" . $row3['sTime'] . "'>" . $row3['sTime'] . "</option>

                   </select>";

            echo "</div>";

        }

    }

}

mysqli_free_result($result_date);
mysqli_free_result($result_movie);
mysqli_free_result($result_time);
// Close connection
mysqli_close($db);

【问题讨论】:

  • 您的代码易受 SQL 注入攻击。您应该使用准备好的语句。
  • 嗨,Kelvin,我们需要更多关于您正在使用的数据以及您想要实现的目标的信息......

标签: php html mysql sql phpmyadmin


【解决方案1】:

您可能希望使用ORDER BY sDatesDate 对您的第一个查询进行排序。

在您的第二个查询中,您再次从 movieScreenings 中进行选择,这不是必需的,因为我想您正在访问的所有数据(海报、标题、描述)都存储在电影列表

第三,在您的最后一个 while 循环中,您将在每个筛选时间重复 &lt;select&gt; 标记。这将导致多个下拉输入。此外,您将在此循环中包含结束 &lt;/div&gt; 标记。所以只循环&lt;option&gt;标签。

通过这些更改,您的代码将如下所示:

$sql_date = "SELECT DISTINCT sDate, sTitle FROM movieScreenings ORDER BY sDate ASC";
$result_date = mysqli_query($db, $sql_date);

while($row = mysqli_fetch_array($result_date)) {
    echo "<h2>" . $row['sDate'] . "</h2>";
    $sql_movie = "SELECT * FROM movieList WHERE title = '" . $row['sTitle'] . "'";
    $result_movie = mysqli_query($db, $sql_movie);

    while($row2 = mysqli_fetch_array($result_movie)) {
        echo "<div class='box'>
              <img class='poster' src='posters/" . $row2['poster'] . "'/>       
              <h2>" . $row2['title'] . "</h2>
              <p>" . $row2['description'] . "</p>";

        $sql_time = "SELECT DISTINCT sTime FROM movieScreenings WHERE sTitle = '" . $row2['title'] . "' AND sDate = '" . $row['sDate'] . "'";
        $result_time = mysqli_query($db, $sql_time);

        echo "<select name='sTime'>";
        while($row3 = mysqli_fetch_array($result_time)) {
            echo "<option value='" . $row3['sTime'] . "'>" . $row3['sTime'] . "</option>";
        }
        echo "</select>";

        echo "</div>";
    }
}

...

最后,我建议您使用 ID 作为您的外键,以防止将来出现重复。可能有多部电影具有相同的标题。

【讨论】:

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