首先要知道 REST 服务的确切 URL。由于您已指定 http://localhost:2517/Service1/Create，现在只需尝试从 IE 打开相同的 URL，您应该得到不允许的方法，因为您的 Create 方法是为 WebInvoke 定义的，而 IE 会执行 WebGet。
现在确保您的客户端应用程序中的 SampleItem 定义在服务器上的同一命名空间中，或者确保您正在构建的 xml 字符串具有适当的命名空间，以便服务识别样本对象的 xml 字符串可以被反序列化回服务器上的对象。
我在我的服务器上定义了 SampleItem，如下所示：
namespace SampleApp
{
public class SampleItem
{
public int Id { get; set; }
public string StringValue { get; set; }
}
}
我的SampleItem对应的xml字符串如下：
<SampleItem xmlns="http://schemas.datacontract.org/2004/07/SampleApp" xmlns:i="http://www.w3.org/2001/XMLSchema-instance"><Id>6</Id><StringValue>from client testing</StringValue></SampleItem>
现在我使用以下方法对 REST 服务执行 POST：
private string UseHttpWebApproach<T>(string serviceUrl, string resourceUrl, string method, T requestBody)
{
string responseMessage = null;
var request = WebRequest.Create(string.Concat(serviceUrl, resourceUrl)) as HttpWebRequest;
if (request != null)
{
request.ContentType = "application/xml";
request.Method = method;
}
//var objContent = HttpContentExtensions.CreateDataContract(requestBody);
if(method == "POST" && requestBody != null)
{
byte[] requestBodyBytes = ToByteArrayUsingDataContractSer(requestBody);
request.ContentLength = requestBodyBytes.Length;
using (Stream postStream = request.GetRequestStream())
postStream.Write(requestBodyBytes, 0, requestBodyBytes.Length);
}
if (request != null)
{
var response = request.GetResponse() as HttpWebResponse;
if(response.StatusCode == HttpStatusCode.OK)
{
Stream responseStream = response.GetResponseStream();
if (responseStream != null)
{
var reader = new StreamReader(responseStream);
responseMessage = reader.ReadToEnd();
}
}
else
{
responseMessage = response.StatusDescription;
}
}
return responseMessage;
}
private static byte[] ToByteArrayUsingDataContractSer<T>(T requestBody)
{
byte[] bytes = null;
var serializer1 = new DataContractSerializer(typeof(T));
var ms1 = new MemoryStream();
serializer1.WriteObject(ms1, requestBody);
ms1.Position = 0;
var reader = new StreamReader(ms1);
bytes = ms1.ToArray();
return bytes;
}
现在我调用上面的方法如图：
SampleItem objSample = new SampleItem();
objSample.Id = 7;
objSample.StringValue = "from client testing";
string serviceBaseUrl = "http://localhost:2517/Service1";
string resourceUrl = "/Create";
string method="POST";
UseHttpWebApproach<SampleItem>(serviceBaseUrl, resourceUrl, method, objSample);
我在客户端也定义了 SampleItem 对象。如果您想在客户端构建xml字符串并通过，那么您可以使用以下方法：
private string UseHttpWebApproach(string serviceUrl, string resourceUrl, string method, string xmlRequestBody)
{
string responseMessage = null;
var request = WebRequest.Create(string.Concat(serviceUrl, resourceUrl)) as HttpWebRequest;
if (request != null)
{
request.ContentType = "application/xml";
request.Method = method;
}
//var objContent = HttpContentExtensions.CreateDataContract(requestBody);
if(method == "POST" && requestBody != null)
{
byte[] requestBodyBytes = ASCIIEncoding.UTF8.GetBytes(xmlRequestBody.ToString());
request.ContentLength = requestBodyBytes.Length;
using (Stream postStream = request.GetRequestStream())
postStream.Write(requestBodyBytes, 0, requestBodyBytes.Length);
}
if (request != null)
{
var response = request.GetResponse() as HttpWebResponse;
if(response.StatusCode == HttpStatusCode.OK)
{
Stream responseStream = response.GetResponseStream();
if (responseStream != null)
{
var reader = new StreamReader(responseStream);
responseMessage = reader.ReadToEnd();
}
}
else
{
responseMessage = response.StatusDescription;
}
}
return responseMessage;
}
对上述方法的调用如下所示：
string sample = "<SampleItem xmlns=\"http://schemas.datacontract.org/2004/07/XmlRestService\" xmlns:i=\"http://www.w3.org/2001/XMLSchema-instance\"><Id>6</Id><StringValue>from client testing</StringValue></SampleItem>";
string serviceBaseUrl = "http://localhost:2517/Service1";
string resourceUrl = "/Create";
string method="POST";
UseHttpWebApproach<string>(serviceBaseUrl, resourceUrl, method, sample);
注意：请确保您的网址正确