在 Asp.Net 中展平和重组 linq [关闭]

Question

我想用旅行列表重构原始 json 数据并根据登机点返回转换后的扁平化列表和落点使用 Linq。下面是原始 json 数据的示例和我想要的结果。我怎么做？请帮忙。谢谢。

原始Json：

[{
     tripId: 1,
     name: "abc express",
     boardingTimes: [
     {
         time: 1200,
         id: 12,
         name: "A"
     },
     {
         time: 1215,
         id: 14,
         name: "B"
     }
     ],
     droppingTimes: [{
         time: 1400,
         id: 15,
         name: "C"
     }]
}]

结果：

[{
         tripId: 1,
         name: "abc express",
         boardingTimes: 
         {
             time: 1200,
             id: 12,
             name: "A"
         },
         droppingTimes: {
             time: 1400,
             id: 15,
             name: "C"
         }
},
         tripId: 1,
         name: "abc express",
         boardingTimes: 
         {
             time: 1215,
             id: 14,
             name: "B"
         },
         droppingTimes: {
             time: 1400,
             id: 15,
             name: "C"
         }
]

Answer 1

您可以使用LINQ-to-JSON API 来完成，它是Json.Net 的一部分：

JArray trips = JArray.Parse(originalJson);

JArray pairs = new JArray(trips
    .Select(trip => 
        new JArray(trip["boardingTimes"]
            .Join(trip["droppingTimes"], bt => 1, dt => 1, (bt, dt) => 
                new JObject(
                    new JProperty("tripId", trip["tripId"]),
                    new JProperty("name", trip["name"]),
                    new JProperty("boardingTimes", bt),
                    new JProperty("droppingTimes", dt)
                )
            )
        )
    )
    .SelectMany(a => a)
);

string flattenedJson = pairs.ToString();

小提琴：https://dotnetfiddle.net/VN1AGM