将动态 JSON 数据插入数据库

Question

我想将 JSON 数据插入到 sql server 表中，我通过 URL 检索我的 json 数据，并且我已经通过明显的错误 {"Must declare the scalar variable \"@Name\"."} 在按钮单击事件上编写了我的插入逻辑，因为我没有提供任何用于插入数据的参数，因为我可以不传递那些硬编码的参数

private string HttpContent(string url)
        {
            WebRequest objRequest = System.Net.HttpWebRequest.Create(url);
            StreamReader sr = new StreamReader(objRequest.GetResponse().GetResponseStream());
            string result = sr.ReadToEnd();
            sr.Close();
            return result;
        }
        protected void btnsave_Click(object sender, EventArgs e)
        {
            var conString = ConfigurationManager.ConnectionStrings["SQLDBConnection"];
            string strConnString = conString.ConnectionString;
            SqlConnection conn = new SqlConnection(strConnString);
            SqlCommand com;
            string data = HttpContent(txturl.Text);
                JavaScriptSerializer jsSerializer = new JavaScriptSerializer();
                var table = jsSerializer.Deserialize<dynamic>(data);
                conn.Open();
                com = new SqlCommand("INSERT INTO tbl_insert_json (Name, Mobile, Email) VALUES(@Name, @Mobile, @Email)", conn);
                com.CommandType = CommandType.Text;
                int refId = com.ExecuteNonQuery();
                conn.Close();
                if (refId > 0)
                {
                    Response.Write("{\"response\":{\"status\":\"success\",\"msg\":\"Details Saved Successfully..\"}}");
                }
                else
                {
                    Response.Write("{\"response\":{\"status\":\"fail\",\"msg\":\"oops!! something went wrong\"}}");
                }
            }

现在我的问题是我应该改变什么或者如何将我的数据插入到 sql server 表中

我使用每个循环来映射每一行然后插入但对我不起作用请分享将数据插入表的任何想法或方法？我在这部分遇到问题com = new SqlCommand("INSERT INTO tbl_insert_json (Name, Mobile, Email) VALUES(@Name, @Mobile, @Email)", conn); 如何将这些参数插入到表中

Answer 1

必须在SqlCommand对象的实例行之后添加参数以将参数替换为json值，例如：

    com = new SqlCommand("INSERT INTO tbl_insert_json (Name, Mobile, Email) VALUES(@Name, @Mobile, @Email)", conn);
    com.Parameters.Add("@Name", SqlDbType.NChar);
    com.Parameters["@Name"].Value = "NameDataJson";

    com.Parameters.Add("@Mobile", SqlDbType.NChar);
    com.Parameters["@Mobile"].Value = "MobileDataJson";

    com.Parameters.Add("@Email", SqlDbType.NChar);
    com.Parameters["@Email"].Value = "EmailDataJson";