xml在web api c#中列出转换答案

【问题标题】：xml to list conversion in web api c#xml在web api c#中列出转换
【发布时间】：2017-04-07 07:18:17
【问题描述】：

我收到一个 xml 格式的请求，我需要使用 web api 将其转换为 c# 中的列表。

这是我收到的请求 xml

<OTA_HotelInvCountNotifRQ xmlns="http://www.zzz.com/OTA/2015/03"
TimeStamp="2015-03-10T09:41:51.982" Version="1.2"> <Inventories 
HotelCode="10001"> <Inventory> <StatusApplicationControl Start="2015-03-16" 
End="2015-03-30" Mon="0" Tue="0" Wed="0" Thur="0" Fri="0" Sat="1" Sun="1" 
InvTypeCode="DLX" AllInvCode="False" /> <InvCounts> <InvCount CountType="2" 
Count="17" /> </InvCounts> </Inventory> <Inventory> 
<StatusApplicationControl Start="2015-03-16" End="2015-03-30" 
AllInvCode="False" Mon="1" Tue="1" Wed="1" Thur="1" Fri="1" Sat="1" Sun="1" 
InvTypeCode="STD"></StatusApplicationControl> <InvCounts> <InvCount 
CountType="2" Count="7" /> </InvCounts> </Inventory> </Inventories> 
</OTA_HotelInvCountNotifRQ>

这是我的 c# 方法

 public HttpResponseMessage UpdateHotelAvailability(HttpRequestMessage request)
        {
            var doc = new XmlDocument();
            doc.Load(request.Content.ReadAsStreamAsync().Result);


            var serializer = new XmlSerializer(typeof(HRootObject));
            using (var reader = XmlReader.Create(doc.InnerXml))
            {
                HRootObject Hobj = (HRootObject)serializer.Deserialize(reader);

            }


            HttpResponseMessage res = Request.CreateResponse(HttpStatusCode.OK, 200);
            return res;
        }

列表对象的c#类

public class sampleclass
    {

        public class StatusApplicationControl
        {
            public string Start { get; set; }
            public string End { get; set; }
            public string Mon { get; set; }
            public string Tue { get; set; }
            public string Wed { get; set; }
            public string Thur { get; set; }
            public string Fri { get; set; }
            public string Sat { get; set; }
            public string Sun { get; set; }
            public string InvTypeCode { get; set; }
            public string AllInvCode { get; set; }
        }

        public class InvCount
        {
            public string CountType { get; set; }
            public string Count { get; set; }
        }

        public class InvCounts
        {
            public InvCount InvCount { get; set; }
        }

        public class Inventory
        {
            public StatusApplicationControl StatusApplicationControl { get; set; }
            public InvCounts InvCounts { get; set; }
        }

        public class Inventories
        {
            public string HotelCode { get; set; }
            public List<Inventory> Inventory { get; set; }
        }

        public class HRootObject
        {
            public string TimeStamp { get; set; }
            public string Version { get; set; }
            public Inventories Inventories { get; set; }
        }
    }

我需要使用上述类将请求 xml 转换为列表。我现在在路径中遇到非法错误。任何帮助将不胜感激。谢谢

更新：

这是我在文档的 innerxml 节点中得到的内容

<OTA_HotelInvCountNotifRQ xmlns="http://www.zzz.com/OTA/2015/03"
TimeStamp="2015-03-10T09:41:51.982" Version="1.2"> <Inventories 
HotelCode="10001"> <Inventory> <StatusApplicationControl Start="2015-03-16" 
End="2015-03-30" Mon="0" Tue="0" Wed="0" Thur="0" Fri="0" Sat="1" Sun="1" 
InvTypeCode="DLX" AllInvCode="False" /> <InvCounts> <InvCount CountType="2" 
Count="17" /> </InvCounts> </Inventory> <Inventory> 
<StatusApplicationControl Start="2015-03-16" End="2015-03-30" 
AllInvCode="False" Mon="1" Tue="1" Wed="1" Thur="1" Fri="1" Sat="1" Sun="1" 
InvTypeCode="STD"></StatusApplicationControl> <InvCounts> <InvCount 
CountType="2" Count="7" /> </InvCounts> </Inventory> </Inventories> 
</OTA_HotelInvCountNotifRQ>

【问题讨论】：

如果您收到“路径中的非法错误”，您必须首先检查路径。一旦可以正确解析路径，就可以使用 LINQ to XML 从 XML 字符串中获取列表。
@A3006 知道怎么做吗？
你现在在 request.Content.ReadAsStreamAsync().Result 得到什么？
@A3006 我在文档的 innerxml 节点中得到了提到的请求 xml。

标签： c# json xml webapi2

【解决方案1】：

试试这个……

public static void ReadInventory()
        {
            XDocument doc = XDocument.Load(@"D:\\Sample\\Data2.xml");
            XNamespace ns = doc.Root.Name.Namespace; // You will need to use this "ns" in every XPATH except attributes. 
            var v = from h in doc.Descendants(ns+"StatusApplicationControl")
                    select new StatusApplicationControl
                    {
                        Start = h.Attribute("Start").Value,
                        End = h.Attribute("End").Value
                    };

            foreach (var item in v)
            {
                Console.Write("Start" + item.Start + " End " + item.End + "\r\n" );
            }

            Console.WriteLine(v.Count());
        }

我只为开始和结束做了这个，但你可以添加剩余的属性。

如果您还有其他问题，请告诉我。

【讨论】：

谢谢，如果 xml 是文件格式，但如果相同的 xml 作为请求发送到 web api 并且当我尝试读取它们时，我在路径错误中得到非法字符

【解决方案2】：

这已经过测试：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;


namespace ConsoleApplication49
{   
    class Program
    {
        const string FILENAME = @"c:\temp\test.xml";
        static void Main(string[] args)
        {
            new Sampleclass(FILENAME);
        }
    }
    public class Sampleclass
    {
        public static HRootObject  hRootObject { get; set; }

        public Sampleclass(string filename)
        {
            XDocument doc = XDocument.Load(filename);
            XNamespace ns = ((XElement)doc.FirstNode).GetDefaultNamespace();

            hRootObject = doc.Elements(ns + "OTA_HotelInvCountNotifRQ").Select(m => new HRootObject() {
                TimeStamp = (DateTime)m.Attribute("TimeStamp"),
                Version = (string)m.Attribute("Version"),
                 Inventories = m.Elements(ns + "Inventories").Select(n => new Inventories() {
                     HotelCode = (string)n.Attribute("HotelCode"),
                     Inventory = n.Elements(ns + "Inventory").Select(o => new Inventory() {
                         StatusApplicationControl = o.Elements(ns + "StatusApplicationControl").Select(p => new StatusApplicationControl() {
                             Start = (DateTime)p.Attribute("Start"),
                             End = (DateTime)p.Attribute("End"),
                             Mon = (int)p.Attribute("Mon"),
                             Tue = (int)p.Attribute("Tue"),
                             Wed = (int)p.Attribute("Wed"),
                             Thur = (int)p.Attribute("Thur"),
                             Fri = (int)p.Attribute("Fri"),
                             Sat = (int)p.Attribute("Sat"),
                             Sun = (int)p.Attribute("Sun"),
                             InvTypeCode = (string)p.Attribute("InvTypeCode"),
                             AllInvCode = (Boolean)p.Attribute("AllInvCode")
                         }).FirstOrDefault(),
                         InvCounts = o.Elements(ns + "InvCounts").Select(p => new InvCounts() {
                             InvCount = p.Elements(ns + "InvCount").Select(q => new InvCount() {
                                 Count = (int)q.Attribute("Count"),
                                 CountType = (int)q.Attribute("CountType")
                             }).FirstOrDefault()
                         }).FirstOrDefault()
                     }).ToList()
                 }).FirstOrDefault()
            }).FirstOrDefault();
        }


        public class StatusApplicationControl
        {
            public DateTime Start { get; set; }
            public DateTime End { get; set; }
            public int Mon { get; set; }
            public int Tue { get; set; }
            public int Wed { get; set; }
            public int Thur { get; set; }
            public int Fri { get; set; }
            public int Sat { get; set; }
            public int Sun { get; set; }
            public string InvTypeCode { get; set; }
            public Boolean AllInvCode { get; set; }
        }

        public class InvCount
        {
            public int CountType { get; set; }
            public int Count { get; set; }
        }

        public class InvCounts
        {
            public InvCount InvCount { get; set; }
        }

        public class Inventory
        {
            public StatusApplicationControl StatusApplicationControl { get; set; }
            public InvCounts InvCounts { get; set; }
        }

        public class Inventories
        {
            public string HotelCode { get; set; }
            public List<Inventory> Inventory { get; set; }
        }

        public class HRootObject
        {
            public DateTime TimeStamp { get; set; }
            public string Version { get; set; }
            public Inventories Inventories { get; set; }
        }
    }


}

【讨论】：

非常感谢您宝贵的时间来回答，但是您从本地系统读取 xml 文件，我将它们作为 Web api 中的请求获取，所以我收到非法字符路径错误。但是如果我从本地 pc 读取 xml 则它工作正常。
如果你要返回一个字符串（innerxml），你可以使用 .Parse(string) 而不是 .Load(Filename)。

【解决方案3】：

感谢 jdweng 和 A3006，我已将您的代码和想法合二为一。如果您期望 xml 中的 Web 请求，请查看下面的 Web api 方法

public HttpResponseMessage UpdateHotelAvailability()
    {

        string incomingText = this.Request.Content.ReadAsStringAsync().Result;
        XDocument doc = XDocument.Parse(incomingText);
        XNamespace ns = doc.Root.Name.Namespace;
        var v = from h in doc.Descendants(ns+"StatusApplicationControl")
                select new StatusApplicationControl
                {
                    Start = h.Attribute("Start").Value,
                    End = h.Attribute("End").Value
                };

        HttpResponseMessage res = Request.CreateResponse(HttpStatusCode.OK, 200);
        return res;
    }

【讨论】：