如何从 WCF 服务获取 XML 输出答案

【问题标题】：How to get XML output from a WCF Service如何从 WCF 服务获取 XML 输出
【发布时间】：2016-09-14 12:49:30
【问题描述】：

我想获得以下给定的 xml 作为 WCF 服务的输出。

<?xml version="1.0" encoding="UTF-8"?>
<payloads>
    <payload>
        <firstname>Sid</firstname>
        <secondname>Singh</secondname>
        <number>1</number>
    </payload>
    <payload>
        <firstname>Deepak</firstname>
        <secondname>Shahi</secondname>
        <number>2</number>
    </payload>
    <payload>
        <firstname>Shorya</firstname>
        <secondname>Garg</secondname>
        <number>3</number>
    </payload>
</payloads>

下面是我的 WCF 服务合同和数据合同：-

[ServiceContract]
public interface IService1
{
    [OperationContract]
    Payload Payloads(Payload Payload);
}

[DataContract(Name = "Payload")]
public class Payload
{
    public string _firstname;
    public string _secondname;
    public string _number;

    [DataMember(Name = "firstname")]
    public string firstname
    {
        get { return _firstname; }
        set { _firstname = value; }
    }

    [DataMember(Name = "secondname")]
    public string secondname
    {
        get { return _secondname; }
        set { _secondname = value; }
    }

    [DataMember(Name = "number")]
    public string number
    {
        get { return _number; }
        set { _number = value; }
    }

}

下面是我的班级：-

public class Service1 : IService1
    {
        public Payload Payloads(Payload Payload)
        {
            if (Payload == null)
            {
                throw new ArgumentNullException("Payload");
            }
            return Payload;
        }
    }

使用我的 WCF，我没有像上面给出的 XML 那样得到我想要的输出。请帮忙。在此先感谢:)

【问题讨论】：

标签： c# xml wcf

【解决方案1】：

你的模型

[XmlRoot(ElementName="payload")]
    public class Payload {
        [XmlElement(ElementName="firstname")]
        public string Firstname { get; set; }
        [XmlElement(ElementName="secondname")]
        public string Secondname { get; set; }
        [XmlElement(ElementName="number")]
        public string Number { get; set; }
    }

    [XmlRoot(ElementName="payloads")]
    public class Payloads {
        [XmlElement(ElementName="payload")]
        public List<Payload> Payload { get; set; }
    }

IServ

 [OperationContract]
              [WebInvoke(Method = "GET",
                  ResponseFormat = WebMessageFormat.Xml,
                  BodyStyle = WebMessageBodyStyle.Bare,
                  UriTemplate = "GetPay")]
              Payload GetPay();

服务

 public Payload GetPay()
            {
                return new Payload();
            }

经过测试和工作。

【讨论】：