使用 XmlDocument 解析肥皂信封的 xml

Question

我开始使用 XmlDocument 在 C# 中解析 XML。我已经关注 xml

<?xml version="1.0" encoding="UTF-8"?>
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
    <soapenv:Body>
        <ns1:getCustomersResponse soapenv:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" xmlns:ns1="http://DefaultNamespace">
            <getCustomersReturn soapenc:arrayType="soapenc:string[2]" xsi:type="soapenc:Array" xmlns:soapenc="http://schemas.xmlsoap.org/soap/encoding/">
                <getCustomersReturn xsi:type="soapenc:string"></getCustomersReturn>
                <getCustomersReturn xsi:type="soapenc:string">some data</getCustomersReturn>
                <getCustomersReturn xsi:type="soapenc:string">some more data</getCustomersReturn>
            </getCustomersReturn>
        </ns1:getCustomersResponse>
    </soapenv:Body>
</soapenv:Envelope>

我的代码：

XmlDocument xmlDocument = new XmlDocument();
xmlDocument.LoadXml(result);  //loading soap message as string
XmlNamespaceManager xmlNamespaceManager = new XmlNamespaceManager(xmlDocument.NameTable);

xmlNamespaceManager.AddNamespace("ns1", "http://DefaultNamespace"); 

XmlNodeList xmlNodeList = xmlDocument.SelectNodes("//ns1:getCustomersResponse/getCustomersReturn", xmlNamespaceManager);

string[] results = new string[xmlNodeList.Count];

var str = "";
var count = 0;
foreach (XmlNode xmlNode in xmlNodeList)
{
    str += xmlNode.InnerText;
}

Assert.IsNull(results, xmlNodeList.Count + ", " + count + ", " + str);

我想将getCustomersReturn 的子节点（文本）检索为string[]

问题：

所有节点都被扁平化为单个字符串而不是数组。

xmlNodeList.Count 是 1 而不是 3

编辑：实施答案后的后续问题

CS1061  'XmlDocument' does not contain a definition for 'SelectNodes' and no extension method 'SelectNodes' accepting a first argument of type 'XmlDocument' could be found (are you missing a using directive or an assembly reference?)

Answer 1

您的代码有一处更改。 换行：

XmlNodeList xmlNodeList = xmlDocument.SelectNodes("//ns1:getCustomersResponse/getCustomersReturn", xmlNamespaceManager);

下面一行

XmlNodeList xmlNodeList = xmlDocument.SelectNodes("//ns1:getCustomersResponse/getCustomersReturn/getCustomersReturn", xmlNamespaceManager);

使用下面的代码，它会给你想要的输出

    XmlDocument xmlDocument = new XmlDocument();
                xmlDocument.LoadXml(result);  //loading soap message as string
                XmlNamespaceManager xmlNamespaceManager = new XmlNamespaceManager(xmlDocument.NameTable);

                xmlNamespaceManager.AddNamespace("ns1", "http://DefaultNamespace");

                XmlNodeList xmlNodeList = xmlDocument.SelectNodes("//ns1:getCustomersResponse/getCustomersReturn/getCustomersReturn", xmlNamespaceManager);

                string[] results = new string[xmlNodeList.Count];

                var str = "";
                var count = 0;
                foreach (XmlNode xmlNode in xmlNodeList)
                {
                    str += xmlNode.InnerText;
                }

                Assert.IsNull(results, xmlNodeList.Count + ", " + count + ", " + str);

Answer 2

仅使用XPath 表达式，此代码很简单，但可以帮助您了解您遇到了什么问题。这个链接可以帮助你理解XPath：https://en.wikipedia.org/wiki/XPath

    var xml = new XmlDocument();
    xml.LoadXml(xmlstring);
    XmlNamespaceManager manager = new XmlNamespaceManager(xml.NameTable);
    manager.AddNamespace("ns1", "http://DefaultNamespace");
    //select all nodes using XPath
    var search = xml.SelectNodes("//ns1:getCustomersResponse/getCustomersReturn//getCustomersReturn",manager);
    //saving XmlNodeList to List<string>
    var r = new List<string>();
    foreach (XmlNode item in search)
        r.Add(item.InnerText);
    string[] ary = r.ToArray(); //convert List<string> to string[]