【发布时间】:2014-11-06 23:06:06
【问题描述】:
我只是想从 MessageInfo 中获取值。这里的发件人是 xml 的摘录。我只想要“发件人”值。我用 XDocument 尝试了很多不同的东西,并想使用 Linq 查询 我试过了,
var query1 = doc.Descendants("MessageInfo").Select(s => new MessageInfo
{
SYSGENID = s.Element("SysGenID").Value,
TIME_STAMP = s.Element("TimeStamp").Value,
SENDER = s.Element("Sender").Value,
RECEIVER = s.Element("Receiver").Value,
ENTITY_CODE = s.Element("EntityCode").Value
}).FirstOrDefault();
query1 返回 null。以下是xml的示例
我也试过了
XDocument doc = XDocument.Load(filePath);
var messageInfo = doc.Root.Elements("MessageInfo");
var res = from m in messageInfo
select new
{
msgInfo = m.Element("MessageInfo").Value
};
<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"
xmlns:xsi="http://www.w3.org/2001/XMLSchema instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<soap:Body>
<PutSchedule xmlns="http://www.nwpp.org/eide">
<MessageInfo>
<SysGenID>4431</SysGenID>
<TimeStamp>2014-08-12T10:34:28.068000</TimeStamp>
<Sender>611</Sender>
<Receiver>WECC</Receiver>
<EntityCode>611</EntityCode>
</MessageInfo>
<Schedules>
<Schedule>
<ScheduleDescription>
<StartTime>2014-08-12T00:00:00</StartTime>
<EndTime>2014-08-15T00:00:00</EndTime>
<AccountCode>259S.NRGREEN_G1.BaseMW</AccountCode>
</ScheduleDescription>
<Quantities>
【问题讨论】: