【发布时间】:2011-07-08 16:43:21
【问题描述】:
这是我的 XML:
<?xml version="1.0" ?>
<AddressValidateResponse>
<Address ID="0">
<FirmName>FIRM NAME, INC</FirmName>
<Address2>123 MAIN ST</Address2>
<City>SOME PLACE</City>
<State>CA</State>
<Zip5>90028</Zip5>
<Zip4>1467</Zip4>
</Address>
<Address ID="1">
<Error>
<Number>-2147219401</Number>
<Source>SOURCE INFO HERE</Source>
<Description>Address Not Found.</Description>
<HelpFile />
<HelpContext>1000440</HelpContext>
</Error>
</Address>
<Address ID="2">
<FirmName>FIRM NAME, INC</FirmName>
<Address2>123 MAIN ST</Address2>
<City>SOME PLACE</City>
<State>CA</State>
<Zip5>90028</Zip5>
<Zip4>1467</Zip4>
</Address>
<Address ID="3">
<FirmName>FIRM NAME, INC</FirmName>
<Address2>123 MAIN ST</Address2>
<City>SOME PLACE</City>
<State>CA</State>
<Zip5>90028</Zip5>
<Zip4>1467</Zip4>
</Address>
<Address ID="4">
<Error>
<Number>-2147219401</Number>
<Source>SOURCE INFO HERE</Source>
<Description>Address Not Found.</Description>
<HelpFile />
<HelpContext>1000440</HelpContext>
</Error>
</Address>
</AddressValidateResponse>
我需要创建两个列表。一个具有有效地址,一个具有错误块。在上面的示例中,第一个列表将包含 3 个地址,第二个列表将包含两个。不确定如何正确过滤查询。谢谢。
我能够让它与以下内容一起工作,但我怀疑有一种更有效的方法来做同样的事情:
var errors = from d in xDoc.Descendants("Address")
from e in d.Elements("Error")
where e.Element("Description").Value.Trim().ToUpper().Contains("ADDRESS NOT FOUND")
select new AddressObject
{
Order = (int)d.Attribute("ID"),
StreetAddress = "NO MATCH FOUND",
OtherAddress = String.Empty,
City = String.Empty,
State = String.Empty,
ZipCode = String.Empty,
ZipPlus4 = String.Empty
};
errorList = errors.ToList();
var addresses = from a in xDoc.Descendants("Address")
from b in a.Elements("FirmName")
where b.Value != String.Empty
select new AddressObject
{
Order = (int)a.Attribute("ID"),
StreetAddress = (string)a.Element("Address2") ?? String.Empty,
OtherAddress = (string)a.Element("Address1") ?? String.Empty,
City = (string)a.Element("City") ?? String.Empty,
State = (string)a.Element("State") ?? String.Empty,
ZipCode = (string)a.Element("Zip5") ?? String.Empty,
ZipPlus4 = (string)a.Element("Zip4") ?? String.Empty
};
validList = addressess.ToList();
【问题讨论】:
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我在上面的编辑中使用 c#
标签: linq-to-xml