System.Xml.XmlException：“=”字符，十六进制值 0x3D，不能包含在名称中[关闭]

Question

当我尝试从 stringReader 加载 XDocument 时，我收到此错误：

System.Xml.XmlException: The '=' character, hexadecimal value 0x3D, cannot be included in a name. Line 1, position 496.
   at System.Xml.XmlTextReaderImpl.Throw(Exception e)
   at System.Xml.XmlTextReaderImpl.Throw(String res, String[] args)
   at System.Xml.XmlTextReaderImpl.ParseElement()
   at System.Xml.XmlTextReaderImpl.ParseElementContent()
   at System.Xml.XmlTextReaderImpl.Read()
   at System.Xml.Linq.XContainer.ReadContentFrom(XmlReader r)
   at System.Xml.Linq.XContainer.ReadContentFrom(XmlReader r, LoadOptions o)
   at System.Xml.Linq.XDocument.Load(XmlReader reader, LoadOptions options)
   at System.Xml.Linq.XDocument.Load(TextReader textReader, LoadOptions options)
   at Rextester.Program.Main(String[] args)

下面是我尝试加载的一段代码：

 public class Program
    {
        public static void Main(string[] args)
        {
             String body = "<ContactBundleMaintainRequestMessage_sync><BasicMessageHeader><ID>b4cf2093e85242259f0b1b9122b75210</ID></BasicMessageHeader><Contact><UUID>4211feec-464c-4bd8-9490-f1041ed95504</UUID><LifeCycleStatusCode>2</LifeCycleStatusCode><GivenName>Carlo</GivenName><MiddleName /><FamilyName>DiBrigida</FamilyName><Relationship><RelationshipBusinessPartnerUUID>00163e11-a664-1ee8-85c3-74c6366e0886</RelationshipBusinessPartnerUUID><RoleCode>BUR027-2</RoleCode></Relationship><GroupwareSubscriptionactionCode="04"><EmployeeUUID>00163e11-a664-1ee8-85c3-74c6366e0886</EmployeeUUID></GroupwareSubscription></Contact></ContactBundleMaintainRequestMessage_sync>";
             StringReader read = new StringReader(body);
             XDocument xDoc = XDocument.Load(read);

        }
    }

您能帮我解决这个问题吗？我用谷歌搜索了很多，但没有得到任何解决方案或解释到底哪里出错了

Answer 1

属性与标签名称之间必须用空格隔开：<GroupwareSubscriptionactionCode="04"> 应为 <GroupwareSubscription actionCode="04">。