【发布时间】:2009-08-28 21:05:18
【问题描述】:
我希望在 SQL Server 2005 中能够以某种方式以表名作为输入来确定构成主键的所有字段。 sp_columns 似乎没有这个字段。关于在哪里看的任何想法?
【问题讨论】:
-
您使用的是什么版本的 SQL Server?
标签: sql sql-server sql-server-2005 primary-key
我希望在 SQL Server 2005 中能够以某种方式以表名作为输入来确定构成主键的所有字段。 sp_columns 似乎没有这个字段。关于在哪里看的任何想法?
【问题讨论】:
标签: sql sql-server sql-server-2005 primary-key
我在我编写的代码生成器中使用它来获取主键:
SELECT i.name AS IndexName,
OBJECT_NAME(ic.OBJECT_ID) AS TableName,
COL_NAME(ic.OBJECT_ID,ic.column_id) AS ColumnName,
c.is_identity, c.user_type_id, CAST(c.max_length AS int) AS max_length,
CAST(c.precision AS int) AS precision, CAST(c.scale AS int) AS scale
FROM sys.indexes AS i
INNER JOIN sys.index_columns AS ic
INNER JOIN sys.columns AS c ON ic.object_id = c.object_id AND ic.column_id = c.column_id
ON i.OBJECT_ID = ic.OBJECT_ID AND i.index_id = ic.index_id
WHERE i.is_primary_key = 1 AND ic.OBJECT_ID = OBJECT_ID('dbo.YourTableNameHere')
ORDER BY OBJECT_NAME(ic.OBJECT_ID), ic.key_ordinal
【讨论】:
实际上,主键 不是表上的索引。也不是聚集索引。是一个约束,所以寻找它的正确位置是sys.key_constraints:
select ic.key_ordinal, cl.name, ic.is_descending_key
from sys.key_constraints c
join sys.indexes i on c.parent_object_id = i.object_id
and c.unique_index_id = i.index_id
join sys.index_columns ic on ic.object_id = i.object_id
and ic.index_id = i.index_id
join sys.columns cl on cl.object_id = i.object_id
and ic.column_id = cl.column_id
where c.type = 'PK'
and 0 = ic.is_included_column
and i.object_id = object_id('<tablename>')
order by ic.key_ordinal
【讨论】:
-- ANSI SQL 兼容并从 SQL70 开始工作:
select kcu.TABLE_SCHEMA, kcu.TABLE_NAME, kcu.CONSTRAINT_NAME, tc.CONSTRAINT_TYPE, kcu.COLUMN_NAME, kcu.ORDINAL_POSITION
from INFORMATION_SCHEMA.TABLE_CONSTRAINTS as tc
join INFORMATION_SCHEMA.KEY_COLUMN_USAGE as kcu
on kcu.CONSTRAINT_SCHEMA = tc.CONSTRAINT_SCHEMA
and kcu.CONSTRAINT_NAME = tc.CONSTRAINT_NAME
and kcu.TABLE_SCHEMA = tc.TABLE_SCHEMA
and kcu.TABLE_NAME = tc.TABLE_NAME
where tc.CONSTRAINT_TYPE in ( 'PRIMARY KEY', 'UNIQUE' )
order by kcu.TABLE_SCHEMA, kcu.TABLE_NAME, tc.CONSTRAINT_TYPE, kcu.CONSTRAINT_NAME, kcu.ORDINAL_POSITION;
-- 特定于 SQL Server 2005:
select s.name as TABLE_SCHEMA, t.name as TABLE_NAME
, k.name as CONSTRAINT_NAME, k.type_desc as CONSTRAINT_TYPE
, c.name as COLUMN_NAME, ic.key_ordinal AS ORDINAL_POSITION
from sys.key_constraints as k
join sys.tables as t
on t.object_id = k.parent_object_id
join sys.schemas as s
on s.schema_id = t.schema_id
join sys.index_columns as ic
on ic.object_id = t.object_id
and ic.index_id = k.unique_index_id
join sys.columns as c
on c.object_id = t.object_id
and c.column_id = ic.column_id
order by TABLE_SCHEMA, TABLE_NAME, CONSTRAINT_TYPE, CONSTRAINT_NAME, ORDINAL_POSITION;
【讨论】:
试试这个:
SELECT *
FROM INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE
WHERE table_name = 'your_table_name'
AND constraint_name LIKE 'PK%'
【讨论】:
select *
from information_schema.Table_Constraints
where Table_Name = @tableName
【讨论】:
我通常会发现...
sp_help <table>
提供了我需要了解的有关表的所有信息(包括索引信息)。
【讨论】:
在 SQL2005 中,这会返回一个命名主键的行,然后给出“index_keys”下的列列表
sp_help myTable
【讨论】:
我最终使用了这个......
select cu.constraint_catalog,
cu.constraint_schema,
cu.table_name,
cu.constraint_name,
constraint_type,
column_name,
ordinal_position
from information_schema.key_column_usage cu
join information_schema.table_constraints as tc
on tc.constraint_catalog = cu.constraint_catalog and
tc.constraint_schema = cu.constraint_schema and
tc.constraint_name = cu.constraint_name and
tc.table_name = cu.table_name
where cu.table_name = 'table_name_goes_here'
order by constraint_name, ordinal_position
【讨论】: