【问题标题】:How to determine the primary key for a table in SQL Server?如何确定 SQL Server 中表的主键?
【发布时间】:2009-08-28 21:05:18
【问题描述】:

我希望在 SQL Server 2005 中能够以某种方式以表名作为输入来确定构成主键的所有字段。 sp_columns 似乎没有这个字段。关于在哪里看的任何想法?

【问题讨论】:

  • 您使用的是什么版本的 SQL Server?

标签: sql sql-server sql-server-2005 primary-key


【解决方案1】:

我在我编写的代码生成器中使用它来获取主键:

SELECT i.name AS IndexName, 
    OBJECT_NAME(ic.OBJECT_ID) AS TableName, 
    COL_NAME(ic.OBJECT_ID,ic.column_id) AS ColumnName, 
    c.is_identity, c.user_type_id, CAST(c.max_length AS int) AS max_length, 
    CAST(c.precision AS int) AS precision, CAST(c.scale AS int) AS scale 
FROM sys.indexes AS i 
INNER JOIN sys.index_columns AS ic 
INNER JOIN sys.columns AS c ON ic.object_id = c.object_id AND ic.column_id = c.column_id 
    ON i.OBJECT_ID = ic.OBJECT_ID AND i.index_id = ic.index_id 
WHERE i.is_primary_key = 1 AND ic.OBJECT_ID = OBJECT_ID('dbo.YourTableNameHere')
ORDER BY OBJECT_NAME(ic.OBJECT_ID), ic.key_ordinal

【讨论】:

    【解决方案2】:

    实际上,主键 不是表上的索引。也不是聚集索引。是一个约束,所以寻找它的正确位置是sys.key_constraints:

    select ic.key_ordinal, cl.name, ic.is_descending_key
    from sys.key_constraints c
    join sys.indexes i on c.parent_object_id = i.object_id
        and c.unique_index_id = i.index_id
    join sys.index_columns ic on ic.object_id = i.object_id
        and ic.index_id = i.index_id    
    join sys.columns cl on cl.object_id = i.object_id
        and ic.column_id = cl.column_id 
    where c.type = 'PK'
        and 0 = ic.is_included_column
        and i.object_id = object_id('<tablename>')
    order by ic.key_ordinal
    

    【讨论】:

      【解决方案3】:

      -- ANSI SQL 兼容并从 SQL70 开始工作:

      select kcu.TABLE_SCHEMA, kcu.TABLE_NAME, kcu.CONSTRAINT_NAME, tc.CONSTRAINT_TYPE, kcu.COLUMN_NAME, kcu.ORDINAL_POSITION
        from INFORMATION_SCHEMA.TABLE_CONSTRAINTS as tc
        join INFORMATION_SCHEMA.KEY_COLUMN_USAGE as kcu
          on kcu.CONSTRAINT_SCHEMA = tc.CONSTRAINT_SCHEMA
         and kcu.CONSTRAINT_NAME = tc.CONSTRAINT_NAME
         and kcu.TABLE_SCHEMA = tc.TABLE_SCHEMA
         and kcu.TABLE_NAME = tc.TABLE_NAME
       where tc.CONSTRAINT_TYPE in ( 'PRIMARY KEY', 'UNIQUE' )
       order by kcu.TABLE_SCHEMA, kcu.TABLE_NAME, tc.CONSTRAINT_TYPE, kcu.CONSTRAINT_NAME, kcu.ORDINAL_POSITION;
      

      -- 特定于 SQL Server 2005:

      select s.name as TABLE_SCHEMA, t.name as TABLE_NAME
           , k.name as CONSTRAINT_NAME, k.type_desc as CONSTRAINT_TYPE
           , c.name as COLUMN_NAME, ic.key_ordinal AS ORDINAL_POSITION
        from sys.key_constraints as k
        join sys.tables as t
          on t.object_id = k.parent_object_id
        join sys.schemas as s
          on s.schema_id = t.schema_id
        join sys.index_columns as ic
          on ic.object_id = t.object_id
         and ic.index_id = k.unique_index_id
        join sys.columns as c
          on c.object_id = t.object_id
         and c.column_id = ic.column_id
       order by TABLE_SCHEMA, TABLE_NAME, CONSTRAINT_TYPE, CONSTRAINT_NAME, ORDINAL_POSITION;
      

      【讨论】:

      • 当然你会想要添加一个“where”子句。其中 TABLE_NAME='mytable'
      • @Nick 你可以编辑帖子而不是添加评论,也可以添加一些代码格式,因为你的查询不容易阅读 +1 为 ANSI 方法虽然
      • 嘘!学习将代码格式化为代码 - 突出显示一个部分并单击工具栏中的“代码”按钮 (010 101) - 请!
      【解决方案4】:

      试试这个:

      SELECT * 
      FROM INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE
      WHERE table_name = 'your_table_name'
        AND constraint_name LIKE 'PK%'
      

      【讨论】:

        【解决方案5】:
        select *
        from information_schema.Table_Constraints
        where Table_Name = @tableName
        

        看到这个MSDN Listing for Table Constraints

        【讨论】:

        • 这并没有得到主键所涉及的列名
        【解决方案6】:

        我通常会发现...

        sp_help <table>
        

        提供了我需要了解的有关表的所有信息(包括索引信息)。

        【讨论】:

          【解决方案7】:

          在 SQL2005 中,这会返回一个命名主键的行,然后给出“index_keys”下的列列表

          sp_help myTable
          

          【讨论】:

            【解决方案8】:

            我最终使用了这个......

            select  cu.constraint_catalog, 
                    cu.constraint_schema, 
                    cu.table_name, 
                    cu.constraint_name, 
                    constraint_type, 
                    column_name, 
                    ordinal_position
            
            from    information_schema.key_column_usage cu 
            
                    join information_schema.table_constraints as tc
                        on tc.constraint_catalog = cu.constraint_catalog and 
                            tc.constraint_schema = cu.constraint_schema and 
                            tc.constraint_name   = cu.constraint_name and 
                            tc.table_name        = cu.table_name
            
            where   cu.table_name = 'table_name_goes_here'
            
            order by constraint_name, ordinal_position
            

            【讨论】:

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