如何在新行中将 JSON 数组数据打印到 Swift3 中的 UILabel 中答案

【问题标题】：How to print the JSON array data into the UILabel in Swift3 at new lines如何在新行中将 JSON 数组数据打印到 Swift3 中的 UILabel 中
【发布时间】：2017-07-21 12:38:21
【问题描述】：

我收到了这样的 JSON 响应：

[
    {
        "days": [
            "Sun",
            "Mon",
            "Tue",
            "Wed",
            "Thu"
        ],
        "times": [
            "09:00-12:00",
            "16:00-21:00"
        ]
    },
    {
        "days": [
            "Fri"
        ],
        "times": [
            "17:00-22:00"
        ]
    }
]

现在我有一个 UILabel，我在其中将日期和时间的文本设置到下一行。 UILabel 文本将如下所示：

周日周一周二周三周四

09:00-12:00

16:00-21:00

周五

17:00 - 22:00

为此，我正在使用代码：

var allDays = ""
var allTimes = ""
var allDaysTimes = ""
for operating in shop.operatingDays! {
  print(operating.days ?? "")
  print(operating.times ?? "")
  for days in operating.days! {
    print(days)
    allDays.append(days)
   // cell.operationalDays.text = allDays
  }
  for times in operating.times! {
    print(times)
    allTimes.append(times + "\n") 
    allDaysTimes = allDays + "\n" + allTimes
  }
  cell.operationalDays.text = allDaysTimes + "\n"
}

但我无法将 Fri 打印到下一行，但它与 Sun、Mon、Tue、Wed、Thu 一起显示在同一行知道如何实现

【问题讨论】：

let v = arrayJSON.flatMap( {(subDict) -> String in let days = subDict["days"]?.joined(separator: " "); let times = subDict["times"]?.joined(separator: "\n"); return days! + "\n" + times! }).joined(separator: "\n"); cell.operationalDays.text = v;?
@ChelseaShawra 你只有一个 UI 标签？

标签： ios json uitableview swift3

【解决方案1】：

试试这个：

var allDays = ""
var allTimes = ""
var allDaysTimes = ""
for operating in shop.operatingDays! {
  print(operating.days ?? "")
  print(operating.times ?? "")
  for days in operating.days! {
    print(days)
    allDays.append(days)
   // cell.operationalDays.text = allDays
  }

  for times in operating.times! {
    print(times)
    allTimes.append(times + "\n") 

  }
  allDaysTimes.append(allDays + "\n" + allTimes)
  allDays = "\n"
  allTimes = ""

}
cell.operationalDays.text = allDaysTimes

【讨论】：

【解决方案2】：

请尝试这样：

for operating in shop.operatingDays! {
    print(operating.days ?? "")
    print(operating.times ?? "")
    cell.operationalDays.text =  operating.days!.joined() + operating.times.joined() + "\n"
}

【讨论】：

你遇到了什么问题？