如何通过单击按钮打开“openFileDialog”？ [复制]

Question

我想通过点击按钮来打开openFileDialog。但我所有的努力都没有成功。

我试过了：

private void button1_Click(object sender, EventArgs e)
        {
            var dialog = new OpenFileDialog();
            if (dialog.ShowDialog() == DialogResult.OK)

            {
                Class1 excel = new Class1(dialog.InitialDirectory, 1);
                string path = dialog.InitialDirectory + ".txt"; //this is to create a text document with the same name
                TextWriter tw = new StreamWriter(path, true);

                tw.Write(excel.ReadCell(0, 0));
                tw.Close();
            }
        }

似乎总是有什么事情发生，但窗口马上消失了。

有人知道你的建议吗？

谢谢

Answer 1

你能试试这个吗？

            using (OpenFileDialog upload = new OpenFileDialog())
                {
                    upload.Filter = "Txt Files|*.txt";
                    upload.Title = "Select File";
                    if (upload.ShowDialog() != DialogResult.OK)
                        return;
                    string filePath= upload.FileName;
                    this.fileName = Path.GetFileName(fileName);
                }