通过分隔符将列文本拆分为R中的多个不同列答案

【问题标题】：Splitting column text by delimiter into multiple different columns in R通过分隔符将列文本拆分为R中的多个不同列
【发布时间】：2022-01-17 02:37:56
【问题描述】：

我有以下问题。我必须将下面的文本分成单独的列。数据是通过网络抓取提取的，我需要对其进行转换以进行分析。例如，我复制了一行，我只需要 "id":357 和 "slug":"journalism/audio" 作为信息。你知道我怎样才能在 R 中转换它吗？下面的代码来自df栏：

{"id":357,"name":"Audio","analytics_name":"Audio","slug":"journalism/audio","position":1,"parent_id":13,"parent_name":"Journalism","color":1228010,"urls":{"web":{"discover":"http://www.kickstarter.com/discover/categories/journalism/audio"}}}

A screenshot sample table of the data I want to transform

【问题讨论】：

标签： r etl reshape

【解决方案1】：

以这样的字符串开头

stri
[1] "\"id\":357,\"name\":\"Audio\",\"analytics_name\":\"Audio\",\"slug\":\"journalism/audio\",\"position\":1,\"parent_id\":13,\"parent_name\":\"Journalism\",\"color\":1228010,\"urls\":{\"web\":{\"discover\":\"http://www.kickstarter.com/discover/categories/journalism/audio"

先将strsplit字符串用逗号分块并去掉引号

d <- gsub( "\"","", strsplit(stri, ",")[[1]] )
[1] "id:357"
[2] "name:Audio"
[3] "analytics_name:Audio"
[4] "slug:journalism/audio"
[5] "position:1"
[6] "parent_id:13"
[7] "parent_name:Journalism"
[8] "color:1228010"
[9] "urls:{web:{discover:http://www.kickstarter.com/discover/categories/journalism/audio"

最后构建数据框

dat <- data.frame( strsplit( d[grep("^id|^slug",d)], ":" ) )[2,]

colnames( dat ) <- data.frame( strsplit( d[grep("^id|^slug",d)], ":" ) )[1,]
dat
   id             slug
2 357 journalism/audio

数据

stri <- "\"id\":357,\"name\":\"Audio\",\"analytics_name\":\"Audio\",\"slug\":\"journalism/audio\",\"position\":1,\"parent_id\":13,\"parent_name\":\"Journalism\",\"color\":1228010,\"urls\":{\"web\":{\"discover\":\"http://www.kickstarter.com/discover/categories/journalism/audio"

【讨论】：

谢谢，该解决方案适用于我的桌子。

【解决方案2】：

离开您在此处提供的一行数据，可能是这样的吗？

library(magrittr)
library(stringr)
library(tidyr)
library(dplyr)

#Toy data.
df <- data.frame(category = '{"id":357,"name":"Audio","analytics_name":"Audio","slug":"journalism/audio","position":1,"parent_id":13,"parent_name":"Journalism","color":1228010,"urls":{"web":{"discover":"http://www.kickstarter.com/discover/categories/journalism/audio"}}}')
df[2, ] <- df[1, ] 


df %>% 
  mutate(ucol = row_number()) %>%
  separate_rows(category, sep = ",") %>% 
  mutate(category = str_replace_all(category, '[\\"\\{\\}]', "")) %>% 
  filter(str_detect(category, "^id|^slug")) %>%
  separate(category, sep = ":", into = c("key", "val")) %>%
  pivot_wider(names_from = key, values_from = val)

# # A tibble: 2 × 3
#    ucol id    slug            
#   <int> <chr> <chr>           
# 1     1 357   journalism/audio
# 2     2 357   journalism/audio

【讨论】：

谢谢，这个解决方案对我很有帮助。未来我会努力提供更好的数据进行测试。您的代码帮助我建立了使用管道并将数据转换为有意义信息的知识。
@user16268585 不客气！！