如何在php中对组中的值求和？

Question

我列出了一个学生的费用详情，代码是，

    <table class="table table-hover">
      <thead>
        <tr>
          <th>Fees Group</th>
          <th>Fees Type</th>
          <th>Fees Amount</th>
          <th>Action</th>
        </tr>
      </thead>
      <tbody>
        <?php
        $total_amount = "0";
        $total_deposite_amount = "0";
        $total_fine_amount = "0";
        $total_discount_amount = "0";
        $total_balance_amount = "0";
        $group_total = 0;
        $group_id = array();

        foreach ($student_due_fee as $key => $fee) {

          foreach ($fee->fees as $fee_key => $fee_value) {
            $fee_paid = 0;
            $fee_discount = 0;
            $fee_fine = 0;
            $alot_fee_discount = 0;
            $group_id = $fee_value->fee_groups_id;


            if ($group_id !== $finalGroupId) {
              $group_total += $fee_value->amount;
              echo $group_total;
            }

            if (!empty($fee_value->amount_detail)) {
              $fee_deposits = json_decode(($fee_value->amount_detail));

              foreach ($fee_deposits as $fee_deposits_key => $fee_deposits_value) {
                $fee_paid = $fee_paid + $fee_deposits_value->amount;
                $fee_discount = $fee_discount + $fee_deposits_value->amount_discount;
                $fee_fine = $fee_fine + $fee_deposits_value->amount_fine;
              }
            }
            $total_amount = $total_amount + $fee_value->amount;
            $total_discount_amount = $total_discount_amount + $fee_discount;
            $total_deposite_amount = $total_deposite_amount + $fee_paid;
            $total_fine_amount = $total_fine_amount + $fee_fine;
            $feetype_balance = $fee_value->amount - ($fee_paid + $fee_discount);
            $total_balance_amount = $total_balance_amount + $feetype_balance;
            ?>
            <tr>
              <td><?php echo $fee_value->name ?></td>
              <td><?php echo $fee_value->type ?></td>
              <td><?php echo $fee_value->amount ?></td>
              <td>
                <div class="btn-group">
                  <?php
                  if ($feetype_balance > 0) {
                    ?>
                    <a href="<?php echo base_url() . 'payment/paytm/' . $fee->id . "/" . $fee_value->fee_groups_feetype_id . "/" . $_SESSION['studentDetails'][0]->id ?>" class="btn btn-xs btn-primary pull-right myCollectFeeBtn"> Pay </a>

                    <?php
                  } else { ?>
                    <h4 class="label label-success"> Paid </h4>
                  <?php }
                  ?>
                </div>
              </td>
            </tr>

          <?php }
        }
        $finalGroupId =  $group_id;
        ?>
      </tbody>
    </table>

将输出显示为，

这里每个组都有三种不同类型的费用，我只需要在一个组下显示这些类型的总和，

Fee Group           Fee Amount         Action
Ist Term - LKG      6000               Pay
IInd Term - LKG     4500               Pay

以上是想要的输出..

我在 foreach 循环中给出了如下内容，

if ($group_id !== $finalGroupId) {
              $group_total += $fee_value->amount;
              echo $group_total;
     }

如果通过迭代的费用组id与fee_value->fee_groups_id不匹配，则进行值的总和，但它不起作用..

请帮助我在 foreach 循环中获得所需的输出..

var_export($student_due_fee); 给出以下结果，

array ( 0 => stdClass::__set_state(array( 'id' => '19', 'student_session_id' => '278', 'fee_session_group_id' => '15', 'is_active' => 'no', 'created_at' => '2018-04-17 05:18:41', 'name' => 'Ist Term - LKG', 'fees' => array ( 0 => stdClass::__set_state(array( 'id' => '19', 'student_session_id' => '278', 'fee_session_group_id' => '15', 'is_active' => 'no', 'created_at' => '2018-04-17 05:18:41', 'fee_groups_feetype_id' => '74', 'amount' => '1000.00', 'due_date' => '2018-04-24', 'fee_groups_id' => '69', 'name' => 'Ist Term - LKG', 'feetype_id' => '1', 'code' => 'ISEMTUTION', 'type' => 'I SEM TUTION FEES', 'student_fees_deposite_id' => '0', 'amount_detail' => '0', )), 1 => stdClass::__set_state(array( 'id' => '19', 'student_session_id' => '278', 'fee_session_group_id' => '15', 'is_active' => 'no', 'created_at' => '2018-04-17 05:18:41', 'fee_groups_feetype_id' => '75', 'amount' => '2000.00', 'due_date' => '2018-04-24', 'fee_groups_id' => '69', 'name' => 'Ist Term - LKG', 'feetype_id' => '2', 'code' => 'IITUTION', 'type' => 'II SEM TUTION FEES', 'student_fees_deposite_id' => '0', 'amount_detail' => '0', )), 2 => stdClass::__set_state(array( 'id' => '19', 'student_session_id' => '278', 'fee_session_group_id' => '15', 'is_active' => 'no', 'created_at' => '2018-04-17 05:18:41', 'fee_groups_feetype_id' => '76', 'amount' => '3000.00', 'due_date' => '2018-04-24', 'fee_groups_id' => '69', 'name' => 'Ist Term - LKG', 'feetype_id' => '3', 'code' => 'SPORTS', 'type' => 'SPORTS FEES', 'student_fees_deposite_id' => '0', 'amount_detail' => '0', )), ), )), 1 => stdClass::__set_state(array( 'id' => '65', 'student_session_id' => '278', 'fee_session_group_id' => '16', 'is_active' => 'no', 'created_at' => '2018-04-17 05:20:20', 'name' => 'IInd Term - LKG', 'fees' => array ( 0 => stdClass::__set_state(array( 'id' => '65', 'student_session_id' => '278', 'fee_session_group_id' => '16', 'is_active' => 'no', 'created_at' => '2018-04-17 05:20:20', 'fee_groups_feetype_id' => '77', 'amount' => '2000.00', 'due_date' => '2018-04-24', 'fee_groups_id' => '70', 'name' => 'IInd Term - LKG', 'feetype_id' => '7', 'code' => 'MAGAZINE', 'type' => 'MAGAZINE, PHOTOS,BAG, ID etc ', 'student_fees_deposite_id' => '0', 'amount_detail' => '0', )), 1 => stdClass::__set_state(array( 'id' => '65', 'student_session_id' => '278', 'fee_session_group_id' => '16', 'is_active' => 'no', 'created_at' => '2018-04-17 05:20:20', 'fee_groups_feetype_id' => '78', 'amount' => '1500.00', 'due_date' => '2018-04-24', 'fee_groups_id' => '70', 'name' => 'IInd Term - LKG', 'feetype_id' => '8', 'code' => 'SCHOLASTICS', 'type' => 'CO - SCHOLASTICS', 'student_fees_deposite_id' => '0', 'amount_detail' => '0', )), 2 => stdClass::__set_state(array( 'id' => '65', 'student_session_id' => '278', 'fee_session_group_id' => '16', 'is_active' => 'no', 'created_at' => '2018-04-17 05:20:20', 'fee_groups_feetype_id' => '79', 'amount' => '1000.00', 'due_date' => '2018-04-24', 'fee_groups_id' => '70', 'name' => 'IInd Term - LKG', 'feetype_id' => '9', 'code' => 'BOOKSUNIFORM', 'type' => 'BOOKS, NOTEBOOKS, UNIFORM', 'student_fees_deposite_id' => '0', 'amount_detail' => '0', )), ), )), )

Answer 1

你分配这么远到晚了

    $finalGroupId =  $group_id;

你在循环中检查它，但它在那里没有定义。

我不知道你打算做什么，否则我会帮助你。此外，通过严格类型检查!== 进行检查的方式，组 ID 永远不会等于最终组，因此无论如何它都会添加它们。

我个人会做一个数组。

$totals = [];

而不是检查这个

if ($group_id !== $finalGroupId) {
    $group_total += $fee_value->amount;
    echo $group_total;
}

我只需在数组中添加一个键（数组键是唯一的）

$totals[$group_id] = $fee_value->amount;

然后在循环之后就做

$total = array_sum($totals);

更新

你说：

@ArtisticPhoenix，如果组 id 不同，我们可以将特定组 id 的总量相加，这样我就制作了该代码。但我知道这是错误的方法，这就是我寻求帮助的原因。

我回答说：

如果它不同，你怎么能把那个特定的组 id 相加，这真的没有意义。您可以对一组相同的组 id 进行求和，但是当它不同时，您不能对特定的组 id 进行求和，因为它与什么不同。

如果你想对组 id 求和，你可以检查你是否已经在数组中设置了它，然后你可以添加到它。

if(!isset($totals[$group_id])){
     //first time add it to array
     $totals[$group_id] = $fee_value->amount;
}else{
     //other times add to existing value (AKA SUM)
     $totals[$group_id] += $fee_value->amount;
}

正如我所说，你不能总结一个不同的，因为它不同于什么。

如果你的意思是它与其他一切都不同，那么你无法总结它，因为它以前从未见过。这意味着你有一个值，你不能对一个值求和。

如果您的意思是它与当前的不同，那么每次您发现与当前不同的一个时，您都会恢复其他所有内容，这在大多数情况下都是浪费精力。

因此，将一个与前一个相同的相加比较容易，如果这就是你的意思，那么这次更新就是你想要的。

如果您的意思是仅对唯一组 ID 求和，我已经在此更新之前向您展示了这一点。因为数组键是唯一的，所以 $totals 数组中的每个项目只能包含一个值，它是最后一个值 presumably 与具有相同 id 的另一个值相同。因此，totals 数组包含每个唯一 id 的值，然后我们对其求和（或不求和，取决于您真正想做的令人困惑的事情）。