【问题标题】:Remove duplicate combinations in MySQL删除 MySQL 中的重复组合
【发布时间】:2017-12-12 14:31:13
【问题描述】:

我的问题和这个问题类似:https://stackoverflow.com/a/7517904
我有 4 个表,我用键 A 和 B 链接它们:

A

A B C 
1 a c 

B

A B D 
1 a d 
1 a e 

C

A B E 
1 a h 
1 a i 

D

A B F 
1 a k 
1 a l 

我想将表格连接在一起,结果应该是:

A B C D E F
1 a c d h k 
1 a c e i l 

我的实际结果是这样的:

A B C D E F 
1 a c d h k
1 a c e h k
1 a c d h l
1 a c e h l 
1 a c e i l
1 a c d i l
1 a c d i k 
1 a c e i k

问题是,我得到了所有组合。我希望尽可能少的行。我尝试了另一个线程的解决方案,使用行号:

SELECT* 
FROM   (SELECT @rowsnum := @rowsnum + 1 AS ae1num, 
               Concat(ae1.a, ae1.b)     AS id, 
               ae1.* 
        FROM A as ae1, 
               (SELECT @rowsnum := 0) r 
        ORDER  BY ae1.a, 
                  ae1.b) ae1 
       LEFT JOIN (SELECT aenum, 
                         Concat(ae111.a, ae111.b) AS id, 
                         aecm.* 
                  FROM   (SELECT @rownum := @rownum + 1 AS aenum, 
                                 Concat(ae11.a, ae11.b) AS id, 
                                 ae11.* 
                          FROM   A as ae11, 
                                 (SELECT @rownum := 0) a 
                          ORDER  BY ae11.a, 
                                    ae11.b) ae111 
                         LEFT JOIN B as aecm 
                                ON ae111.a = aecm.a 
                                   AND ae111.b = aecm.b 
                  ORDER  BY ae111.a, 
                            ae111.b) aec 
              ON ae1.a = aec.a 
                 AND ae1.b = aec.b 
                 AND aec.aenum = ae1.ae1num 

我希望,我把我的问题描述得够清楚了。

【问题讨论】:

标签: mysql sql duplicates combinations


【解决方案1】:

你在说什么,我认为你想要 A连接到B的第一行,C的第一行和D的第一行,并且 A连接到B的第二行,C的第二行和D的第二行

关系数据库在行中没有任何隐含的顺序;如果你想要一个序列,它必须是一个列值。这有充分的理由,但在这里解释太长了。结果是您需要一列用于序列,如下所示:

create table a (a integer, b varchar(1), c varchar(1));
insert into a (a, b, c) values (1, 'a', 'c');

create table b (a integer, b varchar(1), sequence integer, d varchar(1));
insert into b (a, b, sequence, d) values (1, 'a', 1, 'd');
insert into b (a, b, sequence, d) values (1, 'a', 2, 'e');

create table c (a integer, b varchar(1), sequence integer, e varchar(1));
insert into c (a, b, sequence, e) values (1, 'a', 1, 'h');
insert into c (a, b, sequence, e) values (1, 'a', 2, 'i');

create table d (a integer, b varchar(1), sequence integer, f varchar(1));
insert into d (a, b, sequence, f) values (1, 'a', 1, 'k');
insert into d (a, b, sequence, f) values (1, 'a', 2, 'l');

那么查询是:

select distinct
    a.a,
    a.b,
    a.c,
    b.d,
    c.e,
    d.f
from 
    a 
    join 
    b on a.a = b.a and a.b = b.b 
    join 
    c on a.a = c.a and a.b = c.b and c.sequence = b.sequence
    join 
    d on a.a = d.a and a.b = d.b and d.sequence = b.sequence;

结果是:

+---+---+---+---+---+---+
| a | b | c | d | e | f |
+---+---+---+---+---+---+
| 1 | a | c | d | h | k |
| 1 | a | c | e | i | l |
+---+---+---+---+---+---+
2 rows in set (0.00 sec)

【讨论】:

  • 非常感谢,这就是解决方案 :-)
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