JSON C# 解析错误

Question

这是我的 JSON

{
    "3659639": {
        "EventID": 3659639,
        "RaceNum": 2,
        "Meeting": "Newton Abbot",
        "RaceType": "T",
        "Description": "Attheraces.Com Handicap Chase",
        "Distance": "5300m",
        "TrackCondition": "Good",
        "Weather": "Overcast",
        "Abandoned": 0,
        "SuspendDateTime": "2014-06-17 00:00:42.0000000",
        "OutcomeDateTime": "2014-06-17 00:00:00.0000000",
        "EffectiveRaceDate": "2014-06-16",
        "Status": "Paying",
        "Results": [
            {
                "event_id": 3659639,
                "saddle_number": 11,
                "position": 1,
                "status": "Final"
            },
            {
                "event_id": 3659639,
                "saddle_number": 16,
                "position": 2,
                "status": "Final"
            },
            {
                "event_id": 3659639,
                "saddle_number": 17,
                "position": 3,
                "status": "Final"
            }
        ],
        "Dividends": {
            "0": {
                "event_id": 3659639,
                "source": "NSW",
                "pool_type": "Duet",
                "outcome": "11\/16",
                "pool_value": 79.5,
                "interim_dividend": 11.2,
                "final_dividend": 11.2
            },

            "36": {
                "event_id": 3659639,
                "source": "VIC",
                "pool_type": "Trifecta",
                "outcome": "11\/16\/17",
                "pool_value": 1733,
                "interim_dividend": 2746.2,
                "final_dividend": 2746.2
            },
            "37": {
                "event_id": 3659639,
                "source": "VIC",
                "pool_type": "Win",
                "outcome": "11",
                "pool_value": 2541.06,
                "interim_dividend": 25.5,
                "final_dividend": 25.5
            },
            "RunnerProducts": {
                "11": {
                    "TopeTotePlace": 12,
                    "MidTotePlace": 7.3,
                    "TopeToteWin": 29.8,
                    "MidToteWin": 28,
                    "BestOrSP": 29.8
                },
                "16": {
                    "TopeTotePlace": 2.3,
                    "MidTotePlace": 2
                },
                "17": {
                    "TopeTotePlace": 26.4,
                    "MidTotePlace": 24.2
                }
            }
        }
    },



    "3622800": {
        "EventID": 3622800,
        "RaceNum": 2,
        "Meeting": "Albion Park",
        "RaceType": "H",
        "Description": "Seymour Rising Stars Championship C0 Heat One",
        "Distance": "1660m",
        "TrackCondition": "Good",
        "Weather": "Fine",
        "Abandoned": 0,
        "SuspendDateTime": "2014-06-17 15:09:10.0000000",
        "OutcomeDateTime": "2014-06-17 15:08:00.0000000",
        "EffectiveRaceDate": "2014-06-17",
        "Status": "Closed",
        "Results": [

        ],
        "Dividends": {
            "RunnerProducts": [

            ]
        }
    },



    "3679673": {
        "EventID": 3679673,
        "RaceNum": 6,
        "Meeting": "Thirsk",
        "RaceType": "T",
        "Description": "Market Cross Jewellers Handicap",
        "Distance": "1200m",
        "TrackCondition": null,
        "Weather": null,
        "Abandoned": 0,
        "SuspendDateTime": "2014-06-18 02:20:00.0000000",
        "OutcomeDateTime": "2014-06-18 02:20:00.0000000",
        "EffectiveRaceDate": "2014-06-17",
        "Status": "Open",
        "Results": [

        ],
        "Dividends": {
            "RunnerProducts": [

            ]
        }
    }
}

我正在尝试使用 JSON.Net 解析此代码，并且我已尝试过此代码。

var obj = JObject.Parse(json);
var query =
    from JProperty ev in obj.AsJEnumerable()
    from JProperty evid in ev.Value.AsJEnumerable()
    let value = (JObject)evid.Value
    select new
    {
        Description = (string)value["Description"]

    };

我收到此错误“无法将'Newtonsoft.Json.Linq.JValue' 类型的对象转换为'Newtonsoft.Json.Linq.JObject'。”

我还想阅读结果和分红中的 event_id。谁能告诉我我在这里做错了什么

Answer 1

目前，您正在获取属性的属性 - 然后尝试将每个值转换为 JObject，然后采用 that 的 Description。这太深了一层，就像你一样：

• 根对象
• 根对象的每个属性，真正有一个对象作为其值
• 每个值的每个属性...其中大部分只是字符串属性，因此值不能转换为JObject

完全不清楚您为什么使用AsJEnumerable()，但您只需要根对象的属性，这些属性可以通过Properties() 方法轻松获得。同样，不清楚为什么要使用匿名类型，而不仅仅是获取字符串序列。这工作正常：

var query =
    from ev in obj.Properties()
    select (string) ev.Value["Description"];

或者没有查询语法：

var query = obj.Properties.Select(ev => (string) ev.Value["Description"]);

下一步：

我还想阅读结果和分红中的 event_id

在您提供的数据中，它始终与顶级类型中EventID 属性的值相同。所以你最好：

var query =
    from ev in obj.Properties()
    select new { Description = (string) ev.Value["Description"],
                 Id = (string) ev.Value["EventID"] };

如果您真的想获得红利和结果中的值，则需要弄清楚如何处理这些属性中的多个条目。