【问题标题】:return json response when i call post method from android当我从android调用post方法时返回json响应
【发布时间】:2017-12-13 18:47:22
【问题描述】:

我正在构建一个登录页面,我在其中调用一个 restful api 来检查用户名和密码验证,如果状态代码正常,api 返回用户名 ID,我希望能够存储这个 ID 并在以后使用它

signin.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            try {
                RequestQueue requestQueue = Volley.newRequestQueue(SignIn.this);
                String URL = "http://localhost/WebApplication7/api/login";
                JSONObject jsonBody = new JSONObject();
               // jsonBody.put("tblRegisteredUsers_nickName", username.getText().toString().trim());
                jsonBody.put("tblRegisteredUsers_UserName", username.getText().toString().trim());
                jsonBody.put("tblRegisteredUsers_Password", password.getText().toString().trim());



                final String requestBody = jsonBody.toString();

                StringRequest stringRequest = new StringRequest(Request.Method.POST, URL, new Response.Listener<String>() {
                    @Override
                    public void onResponse(String response) {

                        if (response.trim().equals("2013")) {
                            //login authenticated. Start the next activity of your app
                            Toast.makeText(SignIn.this, "Logged In", Toast.LENGTH_SHORT).show();

                            Intent intent = new Intent(getApplicationContext(), MainActivity.class);
                            startActivity(intent);
                        } else {
                            //login failed. prompt to re-enter the credentials
                            Toast.makeText(SignIn.this, "Failed to log In", Toast.LENGTH_SHORT).show();

                            Log.i("VOLLEY", response);
                            Toast.makeText(getApplicationContext(), response.toString(), Toast.LENGTH_SHORT).show();
                        }
                    }
                }, new Response.ErrorListener() {
                    @Override
                    public void onErrorResponse(VolleyError error) {
                        Log.e("VOLLEY", error.toString());
                    }
                }) {
                    @Override
                    public String getBodyContentType() {
                        return "application/json; charset=utf-8";
                    }

                    @Override
                    public byte[] getBody() throws AuthFailureError {
                        try {
                            return requestBody == null ? null : requestBody.getBytes("utf-8");
                        } catch (UnsupportedEncodingException uee) {
                            VolleyLog.wtf("Unsupported Encoding while trying to get the bytes of %s using %s", requestBody, "utf-8");
                            return null;
                        }
                    }

                    @Override
                    protected Response<String> parseNetworkResponse(NetworkResponse response) {
                        String responseString = "";
                        if (response != null) {
                            responseString = String.valueOf(response.statusCode);

// Toast.makeText(getApplicationContext(), responseString, Toast.LENGTH_SHORT).show(); // 可以获取response.headers等更多细节 } 返回 Response.success(responseString, HttpHeaderParser.parseCacheHeaders(response)); } };

                requestQueue.add(stringRequest);
            } catch (JSONException e) {
                e.printStackTrace();
            } catch (Exception e) {
                e.printStackTrace();
            }


        }
    });

这是我的 web api 代码 (vb asp.net)

Public Function login(<FromBody> ByVal users As tblRegisteredUser) As IHttpActionResult
        Try
            Using entities As IAPD_DBEntities = New IAPD_DBEntities()
                Dim username = entities.tblRegisteredUsers.FirstOrDefault(Function(e) e.tblRegisteredUsers_UserName.Equals(users.tblRegisteredUsers_UserName))
                Dim password = entities.tblRegisteredUsers.FirstOrDefault(Function(e) e.tblRegisteredUsers_Password.Equals(users.tblRegisteredUsers_Password))
                If username Is Nothing OrElse password Is Nothing Then



                    Dim message = Request.CreateResponse(HttpStatusCode.BadRequest, "username or password is incorrect")
                    Return message
                Else
                    Dim response = Request.CreateResponse(HttpStatusCode.OK)
                    response.Content = New StringContent(username.tblRegisteredUsers_UserPKID.ToString.Trim.ToString, Encoding.UTF8, "application/json")
                    'Dim message = Request.CreateResponse(HttpStatusCode.Created, username.tblRegisteredUsers_UserPKID.ToString.Trim)
                    'message.Headers.Location = New Uri(Request.RequestUri, "Loged In successfully")
                    Return Ok(username.tblRegisteredUsers_UserPKID.ToString.Trim.ToString)
                End If
            End Using
        Catch e As Exception
            Return BadRequest(e.ToString)
        End Try
    End Function

并且来自 api 的响应是“2013”​​(用户名的 id) 我如何存储此 ID,我的问题是我得到响应为代码 200 而不是用户名的 ID 任何帮助将不胜感激

【问题讨论】:

    标签: android rest android-volley


    【解决方案1】:

    好吧,如果您只想永久存储该值以供以后使用,您可以将其存储在共享首选项或数据库中,这取决于您。我个人更喜欢使用数据库来存储这种用户数据。

    【讨论】:

    • 我的问题是如何存储它,我的响应字符串返回 200 而不是用户名的 id
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