当我单击按钮 Rails 时，从视图中调用自定义控制器操作

Question

我正在为 Rails 中的一个简单的操作调用而苦苦挣扎，我找不到问题所在以及为什么许多解决方案在我的情况下不起作用。我提到我是来自 Java 世界的 Rails 新手。

问题是这样的：
我想在我的视图中有一个按钮，它指向一个控制器动作，一个改变表中列的动作。

routes.rb

post 'punch/userout' => 'punch#userout', :as => :userout

视图：punch\out.erb

 <%= link_to('Out', userout_path, method: :post)  %>

控制器：punch_controller.rb

  
class PunchController  ApplicationController
    before_filter :authorize_admin, only: :index
    layout 'application'
    layout false, :except  => :new 

  # GET method to get all products from database
  def index
    #@punchins = Punchin.all
    @filterrific = initialize_filterrific(
        Punchin,
        params[:filterrific]
    ) or return

    @punchins = @filterrific.find.page(params[:page])

    respond_to do |format|
      format.html
      format.js
    end

    rescue ActiveRecord::RecordNotFound => e
    # There is an issue with the persisted param_set. Reset it.
    puts "Had to reset filterrific params: #{ e.message }"
    redirect_to(reset_filterrific_url(format: :html)) and return
  end

  # GET method for the new product form
  def new
    @punchin = Punchin.new
     if current_user.admin
       redirect_to root_path
=begin
     elsif current_user.punched_in
       redirect_to punch_out_path
=end
     end
  end

  # POST method for processing form data
  def create
    #@punchin.user_id = current_user.id
    #@punchin = Punchin.new(punch_params)
    @punchin = current_user.punchins.build(punch_params)
    @punchin.server_time = Time.now.strftime("%Y-%m-%d %H:%M")
    #@punchin.is_punched = true;

    #get current user from punchin
    @user = @punchin.user
    #set punched on user with true
    @user.punched_in = true;
    #update user
    @user.save
    #@punchin.user.punched_in = true;
    if @punchin.save
      flash[:notice] = 'Punched In!'
      # Tell the Punchinailer to send a notification email after save
      PunchinMailer.punchin_email(@punchin).deliver_later

      redirect_to punch_in_path
    else
      flash[:error] = 'Failed to edit Punch!'

      render :new
    end
  end

  # PUT method for updating in database a product based on id
  def update
    @punchin = Punchin.find(params[:id])
    if @punchin.update_attributes(punch_params)
      flash[:notice] = 'Punchin updated!'
      redirect_to root_path
    else
      flash[:error] = 'Failed to edit Punchin!'
      render :edit
    end
  end

  # DELETE method for deleting a product from database based on id
  def destroy
    @punchin = Punchin.find(params[:id])
    if @punchin.delete
      flash[:notice] = 'Punchin deleted!'
      redirect_to root_path
    else
      flash[:error] = 'Failed to delete this Punchin!'
      render :destroy
    end
  end

  private
  # we used strong parameters for the validation of params
  def punch_params
    params.require(:punchin).permit(:server_time, :address_geoloc, :work_type, :work_desc, :user_id)
  end

  def show
    # method level rendering
    @punchin = Punchin.find(params[:id])
  end

  #when punched in
  def in
  end 

  def userout
    if user_signed_in?
      current_user.update_attributes(:punched_in => false)
    else
      redirect_to new_user_session_path, notice: 'You are not logged in.'
    end
  end
end

关于信息：一拳属于_to :user 和用户有_many :punches

我在 users 表中有一个列，上面写着 punched_in: true/false，我只希望当我从视图中单击链接/按钮时将该列设置为 false。

我尝试了很多解决方案，包括 link_to、button_to、不同的路线等。 在这种情况下，我收到此错误：

找不到 PunchController 的操作“userout”

在其他情况下，我的按钮工作但无法达到我想要的操作。

谢谢！

Answer 1

您的操作是私密的。把它移到专线上面就可以了

Answer 2

我有一些重构给你

def userout
  if user_signed_in?
    current_user.update_attributes(punched_in: false)
    redirect_to punch_out_path, notice: "You've been punched out" # what path do you want to redirect to?
  else
    redirect_to new_user_session_path, notice: 'You are not logged in.'
  end
end

你能从命令行运行“rake routes”吗？里面有路线吗？

当您单击链接时，rails 控制台会显示什么内容。