【发布时间】:2015-10-26 11:06:35
【问题描述】:
我将选择从第三方网站返回值的数据,格式如下 Json 对象,并且该网站使用 Java 语言和 tomcat 数据库构建。
问题如何从该网站获取包含?
服务器说明
网址:http://103.5.126.24/PalmHallServer/coodraw/coodraw!queryAllProduct.action
返回数据 json对象,所有产品信息数组的luckDrawProductList,
{
"LuckDrawProductList": [
{
"BaseTime": 20140119133000,
"CommissionRatio": 10,
"DeductBetCount": 1,
"Detail": "You can enter any amount between ...",
"Enable": 1,
"FreeResDiscount": 1,
"LotteryTime": 20151016164500,
"LuckDrawDesc": "DRAW1",
"LuckDrawDiscount": 1,
"MaxLuckNumLen": 5,
"MaxMoney": 2000000,
"MinLuckNumLen": 5,
"MinMoney": 100,
"NextStartTime": "2015-10-16 12:00:00",
"NextStopTime": "2015-10-16 16:15:00",
"OpenDrawType": -1,
"PeriodUnit": 1,
"PeriodUnitNum": 1,
"Price": 40,
"ProductCode": "DRAW1",
"ProductDesc": "Draw1",
"ProductEndTime": 20990119163000,
"ProductId": 11111,
"ProductType": 11,
"Rate": 0,
"ResTmplProductId": 11111,
"StopTime": 1800,
"ValidPeriod": 2
}
],
"Period": "201510161645"
}
【问题讨论】:
-
你在使用 Gson 吗? @Cambodia_channel
-
我想在 PHP 中使用 httpClient,因为我的团队合作让我不得不使用它
标签: java php json httpclient codeigniter-3