ASP.Net Web APi C# - GetAsync 不返回 XML 响应内容

Question

我正在使用GetAsync() 调用外部服务并在查询字符串中传递参数。当我检查响应中的内容时，我没有看到任何返回，但是它返回 200 OK 并且在提琴手中它正确地返回了 XML 响应。我需要 XML 响应来反序列化为 C# 对象，然后将其进一步保存到 DB。

尝试过的事情：

1) 尝试在 global-app_start() 中添加此设置，但没有帮助

GlobalConfiguration.Configuration.Formatters.XmlFormatter.UseXmlSerializer = true;

2) 创建了一个对象并尝试通过GetAysnc 发送它，但也没有用。

public class Request
    {
        [XmlElement]
        public string XML { get; set; }
        [XmlElement]
        public List<string> ProNumber { get; set; }
    }

2) 我应该尝试在查询字符串中传递参数并期待 json 结果吗？如果我将 mediatyperformatter 添加到application/json？

这是我的代码：

public async Task<HttpResponseMessage> GetData()
{
    string requestString = "&xml=Y&PRONumber=82040X,03117X";
    string result = "";

    string url = @"http://my.yrc.com/dynamic/national/servlet?CONTROLLER=com.rdwy.ec.rextracking.http.controller.PublicTrailerHistoryAPIController";
    try
    {
        using (var client = new HttpClient())
        {
            client.BaseAddress = new Uri(url);
            client.DefaultRequestHeaders.Accept.Clear();
            client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/xml"));

            HttpResponseMessage response = await client.GetAsync(url+requestString);

            if (response.IsSuccessStatusCode)
            {
                return response;
            }
        }
    }
    catch (Exception ex)
    {
        result = ex.Message;
    }
    return null;
}

编辑：

                        Shipments scp = null;
                        XmlRootAttribute xRoot = new XmlRootAttribute();
                        xRoot.ElementName = "Shipment";
                        xRoot.IsNullable = true;
                        XmlSerializer serializer = new XmlSerializer(typeof(Shipment), xRoot);

                    using (Stream stream = response.Content.ReadAsStreamAsync().Result)
                    {
                        scp = (Shipments)serializer.Deserialize(stream);
                    }

型号：

public class Shipments
    {
        [XmlArrayItem(Type = typeof(Shipment))]
        public Shipment[] Shipment;
    }

    public class Shipment
    {
        [XmlAttribute()]
        public int returnCode { get; set; }
        .................
        ..............

出现错误：<SHIPMENTS xmlns=''> was not expected.

非常感谢您对此的任何帮助。

谢谢， WH

Answer 1

这对我有用 -

var client = new HttpClient();
var data = client.GetStringAsync("http://my.yrc.com/dynamic/national/servlet?CONTROLLER=com.rdwy.ec.rextracking.http.controller.PublicTrailerHistoryAPIController&xml=Y&PRONumber=82040X,03117X").Result;
var ser = new XmlSerializer(typeof(Shipments));
var t = (Shipments)ser.Deserialize(new StringReader(data));


public class Shipment
{
    public string returnCode { get; set; }
    public string returnMessage { get; set; }
    public string freightBillNumber { get; set; }
    //props
}

[XmlRoot(ElementName = "SHIPMENTS")]
public class Shipments
{
    [XmlElement(ElementName = "SHIPMENT")]
    public List<Shipment> SHIPMENT { get; set; }
}

编辑

这也有效 -

var data = client.GetStreamAsync("http://my.yrc.com/dynamic/national/servlet?CONTROLLER=com.rdwy.ec.rextracking.http.controller.PublicTrailerHistoryAPIController&xml=Y&PRONumber=82040X,03117X").Result;

编辑

同样有效 -

var client = new HttpClient();
var data = client.GetAsync("http://my.yrc.com/dynamic/national/servlet?CONTROLLER=com.rdwy.ec.rextracking.http.controller.PublicTrailerHistoryAPIController&xml=Y&PRONumber=82040X,03117X").Result;

var ser = new XmlSerializer(typeof(Shipments));
var t = (Shipments)ser.Deserialize(data.Content.ReadAsStreamAsync().Result);