【发布时间】:2021-01-27 06:52:20
【问题描述】:
我有一个看起来像这样的 github 操作:
const http = require('http');
const core = require('@actions/core');
const options = {
hostname: 'mydomain.com',
port: 80,
path: '/webhook',
method: 'POST',
headers: {
'Content-Type': 'application/x-www-form-urlencoded',
}
};
const postData = {
foo: 'bar'
}
try {
const strPostData = querystring.stringify(postData);
options.headers['Content-Length'] = Buffer.byteLength(strPostData);
const req = http.request(options)
req.write(strPostData)
req.end()
} catch (error) {
core.info(error.message);
}
如果mydomain.com/webhook 离线,我的作业在此操作上失败,记录:
events.js:187
throw er; // Unhandled 'error' event
^
Error: connect ECONNREFUSED xxx.xxx.xxx.xxx:80
at TCPConnectWrap.afterConnect [as oncomplete] (net.js:1129:14)
Emitted 'error' event on ClientRequest instance at:
at Socket.socketErrorListener (_http_client.js:406:9)
at Socket.emit (events.js:210:5)
at emitErrorNT (internal/streams/destroy.js:92:8)
at emitErrorAndCloseNT (internal/streams/destroy.js:60:3)
at processTicksAndRejections (internal/process/task_queues.js:80:21) ***
errno: 'ECONNREFUSED',
code: 'ECONNREFUSED',
syscall: 'connect',
address: 'xxx.xxx.xxx.xxx',
port: 80
***
为什么会失败,为什么try catch 没有捕捉到这个?
如果此操作失败,我不希望整个作业都失败,那么如何捕获此失败并将其隐藏在 GitHub 运行器中?
【问题讨论】:
-
我相信错误是异步的,你需要监听像
'error'这样的事件来捕捉它。另外我注意到您在发送数据之前没有等待连接请求,我不确定您是否这样做。
标签: github-actions