【问题标题】：adding info window on click on marker in google map在谷歌地图中点击标记添加信息窗口
【发布时间】：2017-07-26 10:21:50
【问题描述】：

我正在使用 PHP 和 MYSQL 来从数据库中检索数据并在 Google Map API 上显示标记，并添加了一个信息窗口，其中包括使用 click-Listener 从数据库中检索到的信息。添加信息窗口后，它似乎不起作用。

我的错误在哪里？

代码：

<?php
        /*
        Template Name: MAP2
        */

        get_header();
  ?>


<!DOCTYPE html>
<html>
  <head>
    <title>Custom Markers</title>
    <meta name="viewport" content="width=device-width, initial-scale=1.0, user-scalable=no">
    <meta charset="utf-8">
    <script async defer
    src="https://maps.googleapis.com/maps/api/js?key=AIzaSyCquey2tCZ32jLJJDEEi2D7_RnXXyj9RTI&callback=initMap">
    </script>
     <style>
      /* Always set the map height explicitly to define the size of the div
       * element that contains the map. */
      #map {
        height: 600px;
      }
      /* Optional: Makes the sample page fill the window. */
      html, body {
        height: 100%;
        margin: 0;
        padding: 0;
      }
    </style>

  </head>
  <body>
    <div id="map">
      <div class="map-popupstring hidden" id="popupstring1">
                <div class="text-center">
                    <h3>title</h3>
                     <p>subinfo</p>
                </div>
            </div>

    </div>

    <script>

     var map;
      function initMap() {
        map = new google.maps.Map(document.getElementById('map'), {
          zoom: 8,
          center: new google.maps.LatLng(33.888630, 35.495480),
          mapTypeId: 'roadmap'
        });

        var iconBase = 'https://maps.google.com/mapfiles/kml/shapes/';
        var icons = {
          parking: {
            icon: iconBase + 'parking_lot_maps.png'
          },
          library: {
            icon: iconBase + 'library_maps.png'
          },
          info: {
            icon: iconBase + 'info-i_maps.png'
          }
        };


        var $popup = $("#popupstring1")

        function addMarker(feature) {
          var marker = new google.maps.Marker({
            position: feature.position,
            //icon: icons[feature.type].icon,
            data-popupstring-id: $popup,
            map: map
          });
        }



        var features = [
        <?php
          global $wpdb;
            $prependStr ="";
            foreach( $wpdb->get_results("SELECT siteID, latitude, longitude FROM site_coordinates2", OBJECT) as $key => $row) {
               $latitude = $row->latitude;
               $longitude = $row->longitude;
               $info = $row->siteID;
           echo $prependStr;
       ?>
{
    position: new google.maps.LatLng(<?php echo $latitude; ?>, <?php echo $longitude; ?>),
    type: '<?php echo $info; ?>'
}
<?php
$prependStr =",";
}
?>
        ];

    var infowindow = new google.maps.InfoWindow();

        for (var i = 0, feature; feature = features[i]; i++) {

          addMarker(feature);
        }
}



         </script>


  </body>
</html>

<?php
get_footer();
?>

【问题讨论】：

Google Map pop -up windows doesn't show anything inside it的可能重复

标签： javascript php mysql google-maps

【解决方案1】：

           <div class="map-popupstring hidden" id="popupstring1">
                <div class="text-center">
                    <h3>title</h3>
                     <p>subinfo</p>
                </div>
            </div>

您必须在 html 标签中放入想要的弹出窗口。和谷歌地图标签中的代码来初始化它。并使用data-popupstring-id="#popupstring1" 标签在单击标记时对其进行初始化。

var $popup = $("#popupstring1")

function addMarker(feature) {
      var marker = new google.maps.Marker({
        position: feature.position,
        data-popupstring-id: $popup,
        map: map
      });
    }

【讨论】：

我不知道如何将您的答案放入代码中，我是 Google Map API 的新手
你把html放在<div id="map"></div>下面
我试过你的答案，但它不起作用我将编辑代码并显示编辑后的代码
我对此一无所知。对不起。

【解决方案2】：

我通过添加以下代码解决了这个问题：

代码：

 var popup = new google.maps.InfoWindow({
                    content: feature,
                    maxWidth: 300
                });

          google.maps.event.addListener(marker, "click", function() {
                    if (currentPopup != null) {
                        currentPopup.close();
                        currentPopup = null;
                    }
                    popup.open(map, marker);
                    currentPopup = popup;
                });
                google.maps.event.addListener(popup, "closeclick", function() {
                    map.panTo(center);
                    currentPopup = null;
                });

【讨论】：