【发布时间】:2016-10-26 13:12:59
【问题描述】:
我想在 tornado 的异步 GET 请求处理程序中运行一个慢速阻塞方法(实际上来自第 3 方库)。让方法只是:
def blocking_method(uid):
print("slow method started: ", uid)
time.sleep(10)
print("slow method done: ", uid)
return "slow method ({}) result".format(uid)
此外,我更喜欢在 asyncio 的事件循环中运行 tornado 服务器:
if __name__ == '__main__':
tornado.platform.asyncio.AsyncIOMainLoop().install()
loop = asyncio.get_event_loop()
loop.run_until_complete(make_app())
loop.run_forever()
我知道 @run_in_executor 装饰器,但它不适合我,因为我使用 asyncio。要在异步协程中运行阻塞方法,我应该使用asyncio.get_event_loop() 的run_in_executor 方法。这是一个如何做到这一点的例子,来自this 答案:
import asyncio
async def main():
loop = asyncio.get_event_loop()
executor = concurrent.futures.ThreadPoolExecutor(max_workers=4)
future1 = loop.run_in_executor(executor, blocking_method, 1)
future2 = loop.run_in_executor(executor, blocking_method, 2)
response1 = await future1
response2 = await future2
print(response1)
print(response2)
if __name__ == '__main__':
loop = asyncio.get_event_loop()
loop.run_until_complete(main())
而且效果很好,这是之前脚本的输出:
slow method started: 1
slow method started: 2
slow method done: 2
slow method done: 1
slow method (1) result
slow method (2) result
但如果我在 tornado 的 RequestHandler 的 async def get 方法中使用完全相同的技术:
class AsyncHandler(tornado.web.RequestHandler):
async def get(self):
# simple counter to distinguish requests
self.application.counter += 1
in_msg = "Registered request #{}, working...".format(self.application.counter)
print(in_msg)
loop = asyncio.get_event_loop()
future = loop.run_in_executor(self.application.executor,
blocking_method,
self.application.counter)
result = await future
out_msg = "Request processed, result: {}".format(result)
print(out_msg)
self.write(out_msg)
它阻塞了处理程序的方法。换句话说,如果我在多个浏览器选项卡中打开http://localhost:8888/(假设是两个),那么我期望两个请求并行工作,输出如下:
Registered request #1, working...
slow method started: 1
Registered request #2, working...
slow method started: 2
slow method done: 1
Request processed, result: slow method (1) result
slow method done: 2
Request processed, result: slow method (2) result
但是请求被执行结果:
Registered request #1, working...
slow method started: 1
slow method done: 1
Request processed, result: slow method (1) result
Registered request #2, working...
slow method started: 2
slow method done: 2
Request processed, result: slow method (2) result
那么,我哪里错了?我应该怎么做才能允许并行执行请求处理程序?
这是描述我的问题的完整脚本:
import asyncio
import concurrent.futures
import time
import tornado.web
import tornado.platform
def blocking_method(uid):
print("slow method started: ", uid)
time.sleep(10)
print("slow method done: ", uid)
return "slow method ({}) result".format(uid)
class AsyncHandler(tornado.web.RequestHandler):
async def get(self):
# simple counter to distinguish requests
self.application.counter += 1
in_msg = "Registered request #{}, working...".format(self.application.counter)
print(in_msg)
loop = asyncio.get_event_loop()
future = loop.run_in_executor(self.application.executor,
blocking_method,
self.application.counter)
result = await future
out_msg = "Request processed, result: {}".format(result)
print(out_msg)
self.write(out_msg)
async def make_app():
handlers = [(r"/", AsyncHandler)]
app = tornado.web.Application(handlers, debug=True)
app.executor = concurrent.futures.ThreadPoolExecutor(max_workers=4)
app.counter = 0
app.listen(8888)
if __name__ == '__main__':
tornado.platform.asyncio.AsyncIOMainLoop().install()
loop = asyncio.get_event_loop()
loop.run_until_complete(make_app())
loop.run_forever()
【问题讨论】:
-
run_in_executor不会阻止,它是您的网络浏览器按顺序运行请求。看到这个similar question。
标签: python tornado python-asyncio