【发布时间】:2015-10-01 12:26:07
【问题描述】:
Video
-------
id
source_low
source_med
source_high
Source
--------
id
duration
thumbnail
视频项可以包含至少 1 个或最多 3 个源(低源、中源、高源)。
这个想法与 youtube 相同,这意味着视频记录可以包含多种质量。因此,当我返回持续时间/缩略图时,我想检查哪个源存在并返回其中一个。
例如,如果视频有 source_low 或 source_med ,这意味着 source_low 和 source_med 有持续时间和缩略图,那么我只需要返回其中一个。
Codeigniter 语法:
$this->db->select('v.*, sl.duration, sm.duration as duration_m, sh.duration as duration_h, sl.thumbnail, sm.thumbnail as thumbnail_m, sh.thumbnail as thumbnail_h');
$this->db->from('video as v');
$this->db->join('source as sl', 'v.source_low = sl.video_id', 'left');
$this->db->join('source as sm', 'v.source_med = sm.video_id', 'left');
$this->db->join('source as sh', 'v.source_high = sh.video_id', 'left');
$this->db->group_by('v.id');
SQL(缩略图获取方式相同):
SELECT v.*, sl.duration, sm.duration as duration_sm, sh.duration as duration_sh
FROM video as v
LEFT JOIN source as sl ON (v.source_low = sl.video_id)
LEFT JOIN source as sm ON (v.source_med = sm.video_id)
LEFT JOIN source as sh ON (v.source_high = sh.video_id)
GROUP BY v.id;
现在我可以返回所有的结果,包括空值,但是我怎样才能只返回一个持续时间和一个缩略图呢?
感谢您的帮助
更新:
只需更新查询,但似乎 codeigniter 在处理它时出现了一些错误, 任何想法?谢谢
我的代码:
$this->db->select('v.*, COALESCE(b.duration, bt.duration, bc.duration) AS duration, COALESCE(b.thumbnail, bt.thumbnail, bc.thumbnail) AS thumbnail');
在 SQL 中:
Error Number: 1064
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'AS duration, COALESCE(b.thumbnail, `bt`.`thumbnail`, `bc`.`thumbnail)` AS thumbn' at line 1
SELECT `v`.*, `t`.`name`, `t`.`name_tw`, `t`.`name_cn`, COALESCE(b.duration, `bt`.`duration`, `bc`.`duration)` AS duration, COALESCE(b.thumbnail, `bt`.`thumbnail`, `bc`.`thumbnail)` AS thumbnail FROM (`video` as v) JOIN `teacher` as t ON `v`.`teacher_id` = `t`.`id` LEFT JOIN `brightcove` as b ON `v`.`video` = `b`.`video_id` LEFT JOIN `brightcove` as bt ON `v`.`video_tw` = `bt`.`video_id` LEFT JOIN `brightcove` as bc ON `v`.`video_cn` = `bc`.`video_id` WHERE `v`.`is_delete` = 0 AND `v`.`type` = 0 GROUP BY `v`.`id` ORDER BY `v`.`start_date` desc
【问题讨论】:
-
这是一个很好的问题,但是很难调试您的 SQL,因为它包含在所有不相关的
php字符串中。摆脱这些,只需向我们展示 SQL,我们就能提供帮助! -
谢谢。很抱歉造成混淆,它是 codeigniter 查询,我将其转换为 SQL one
-
您添加的错误消息与您那里的代码不匹配。
-
你的代码有
v.*, COALESCE(...,但在错误信息上你有t.name、t.name_tw等等 -
谢谢,在 codeigniter 中,只需在 select 查询中添加 false 作为第二个参数即可
标签: php mysql sql database codeigniter