【发布时间】:2012-09-28 00:16:15
【问题描述】:
我正在尝试从 C# 应用程序调用 ant 脚本。我希望控制台窗口弹出并保持不变(我现在只是调用命令提示符,但我最终想调用一个 ant 脚本,这可能需要一个小时)。这是我正在使用的代码,我从original 更改:
public void ExecuteCommandSync(object command)
{
try
{
// create the ProcessStartInfo using "cmd" as the program to be run,
// and "/c " as the parameters.
// Incidentally, /c tells cmd that we want it to execute the command that follows,
// and then exit.
System.Diagnostics.ProcessStartInfo procStartInfo =
new System.Diagnostics.ProcessStartInfo("cmd", "/k " + command);
// The following commands are needed to redirect the standard output.
// This means that it will be redirected to the Process.StandardOutput StreamReader.
procStartInfo.RedirectStandardOutput = true;
procStartInfo.UseShellExecute = false;
// Do not create the black window.
procStartInfo.CreateNoWindow = false;
// Now we create a process, assign its ProcessStartInfo and start it
System.Diagnostics.Process proc = new System.Diagnostics.Process();
proc.StartInfo = procStartInfo;
proc.Start();
proc.WaitForExit();
}
catch (Exception objException)
{
Console.WriteLine(objException);
}
}
我还想传入最多 5 个参数,但现在我只关心让窗口保持足够长的时间以查看正在发生的事情,而且我对阅读 ant 脚本生成的任何内容不感兴趣.我不想让任何人为我做我的工作,但我一直在努力解决这个问题,所以任何帮助都将不胜感激!
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