【发布时间】:2017-06-25 17:50:40
【问题描述】:
我需要通过pom.xml 中的键从外部属性文件中获取值。属性文件的位置在src/main/resources/dev.properties。
我试图通过使用 Maven 中的属性来解决这个问题。请帮我。
pom.xml:
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>Simple_project</groupId>
<artifactId>Project</artifactId>
<packaging>war</packaging>
<version>0.0.1-SNAPSHOT</version>
<name>Project Maven Webapp</name>
<url>http://maven.apache.org</url>
<dependencies>
<dependency>
<groupId>junit</groupId>
<artifactId>junit</artifactId>
<version>3.8.1</version>
<scope>test</scope>
</dependency>
<dependency>
<groupId>javax.servlet</groupId>
<artifactId>servlet-api</artifactId>
<version>2.5</version>
</dependency>
</dependencies>
<build>
<finalName>${Project.Name}</finalName>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-war-plugin</artifactId>
<configuration>
<outputDirectory>${path}</outputDirectory>
</configuration>
</plugin>
</plugins>
</build>
</project>
// properties File
dev.properties:
projectPath=/home/user/warfile
Project.Name = newProject
Thanks & Regards,
Tharanya B
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标签: maven