如何使用 Dataweave 2.0 将 JSON 对象组合到另一个嵌套的 JSON 对象中答案

【问题标题】：How to combine a JSON object inside another nested JSON object using Dataweave 2.0如何使用 Dataweave 2.0 将 JSON 对象组合到另一个嵌套的 JSON 对象中
【发布时间】：2021-11-10 07:43:05
【问题描述】：

我有两个输入负载，我想将另一个嵌套 JSON 对象中的 JSON 对象组合到特定对象。预期的输出是将输入 2 与“Response_Data”下的输入 1 结合起来。

我尝试过，但我可以在最后合并输入 2，但无法将其添加到“Response_Data”中。

有人可以帮我写 dataweave 代码吗？

输入 1：

[{
    "Org_Response": {
        "Request_Criteria": {
            "Org_Type_Reference": {
                "ID": {
                    "type": "Org_Type",
                    "text": "Business_Unit"
                }
            },
            "Include_Inactive": "0"
        },
        **"Response_Data"**: {
            "Org": {
                "Reference": {
                    "ID": {
                        "type": "Business_Unit_Reference_ID",
                        "text": "999-99-FD"
                    }
                },
                "Org_Data": {
                    "Reference_ID": "999-99-FD",
                    "Name": "Management"
                }
            }
        }
    }
}]

输入 2：

{
    "Org": {
        "Reference": {
            "ID": {
                "type": "Business_Unit_Reference_ID",
                "text": "90000"
            }
        },
        "Org_Data": {
            "Reference_ID": "90000",
            "Name": "TAXES"
        }
    }
}

预期输出：

[{
    "Org_Response": {
        "Request_Criteria": {
            "Org_Type_Reference": {
                "ID": {
                    "type": "Org_Type",
                    "text": "Business_Unit"
                }
            },
            "Include_Inactive": "0"
        },
        **"Response_Data"**: {
            "Org": {
                "Reference": {
                    "ID": {
                        "type": "Business_Unit_Reference_ID",
                        "text": "999-99-FD"
                    }
                },
                "Org_Data": {
                    "Reference_ID": "999-99-FD",
                    "Name": "Management"
                }
            },
            "Org": {
                "Reference": {
                    "ID": {
                        "type": "Business_Unit_Reference_ID",
                        "text": "90000"
                    }
                },
                "Org_Data": {
                    "Reference_ID": "90000",
                    "Name": "TAXES"
                }
            }
        }
    }
}]

提前致谢

【问题讨论】：

标签： dataweave

【解决方案1】：

有两个选项可以做到这一点，但最好是遍历第一个输入，然后相应地添加第二个输入，但您可以暂时尝试以下方法 -

第一个 DW -

%dw 2.0
output application/json
var input1=[{
    "Org_Response": {
        "Request_Criteria": {
            "Org_Type_Reference": {
                "ID": {
                    "type": "Org_Type",
                    "text": "Business_Unit"
                }
            },
            "Include_Inactive": "0"
        },
        "Response_Filter": {
            "Page": "1",
            "Count": "999"
        },
        "**Response_Data**": {
            "Org": {
                "Reference": {
                    "ID": {
                        "type": "Business_Unit_Reference_ID",
                        "text": "999-99-FD"
                    }
                },
                "Org_Data": {
                    "Reference_ID": "999-99-FD",
                    "Name": "Management"
                }
            }
        }
    }
}]
var input2= [{
    "Org": {
        "Reference": {
            "ID": {
                "type": "Business_Unit_Reference_ID",
                "text": "90000"
            }
        },
        "Org_Data": {
            "Reference_ID": "90000",
            "Name": "TAXES"
        }
    }
}]
---
Org_Response : 
([input1[0].Org_Response - "**Response_Data**"] ++
(input1.Org_Response."**Response_Data**" ++ input2))

第二个 DW -

%dw 2.0
output application/json
var input1=[{
    "Org_Response": {
        "Request_Criteria": {
            "Org_Type_Reference": {
                "ID": {
                    "type": "Org_Type",
                    "text": "Business_Unit"
                }
            },
            "Include_Inactive": "0"
        },
        "Response_Filter": {
            "Page": "1",
            "Count": "999"
        },
        "**Response_Data**": {
            "Org": {
                "Reference": {
                    "ID": {
                        "type": "Business_Unit_Reference_ID",
                        "text": "999-99-FD"
                    }
                },
                "Org_Data": {
                    "Reference_ID": "999-99-FD",
                    "Name": "Management"
                }
            }
        }
    }
}]
var input2= [{
    "Org": {
        "Reference": {
            "ID": {
                "type": "Business_Unit_Reference_ID",
                "text": "90000"
            }
        },
        "Org_Data": {
            "Reference_ID": "90000",
            "Name": "TAXES"
        }
    }
}]
---
Org_Response : input1.Org_Response map {
($ mapObject ((value, key, index) ->
{
     ((key) : value) if (key as String != "**Response_Data**"),
    ((key) : [value] + input2) if (key as String == "**Response_Data**")
}
 ))
}

【讨论】：

【解决方案2】：

脚本

%dw 2.0
output application/json
var inp2= {
    "Org": {
        "Reference": {
            "ID": {
                "type": "Business_Unit_Reference_ID",
                "text": "90000"
            }
        },
        "Org_Data": {
            "Reference_ID": "90000",
            "Name": "TAXES"
        }
    }
}
var respData = payload.Org_Response."**Response_Data**"
var respDataNew = respData + inp2
---
[Org_Response: payload[0].Org_Response - "**Response_Data**" ++ 
{
    "**Response_Data**": respDataNew
}]

【讨论】：