【发布时间】:2019-11-15 08:28:29
【问题描述】:
文件夹文档:
{"_id":"5d1e2da512ad38225af60869","id":1,"name":"inbox","must":true}
{"_id":"5d1e2da512ad38225af6086b","id":2,"name":"outbox","must":true}
{"_id":"5d1e2da512ad38225af6086d","id":3,"name":"drafts","must":true}
{"_id":"5d1e2da512ad38225af6086f","id":4,"name":"trash","must":true}
邮件文件:
{"_id":"5d1e2da512ad38225af60871","id":1,"isdeleted":true,"foldersids":[1],"subject":"Hello1","body":"Hello this is mail 1"}
{"_id":"5d1e2da512ad38225af60873","id":2,"isdeleted":false,"foldersids":[1],"subject":"Hello2","body":"Hello this is mail 2"}
我正在尝试获取所有未标记为已删除的邮件,并仅获取其 Id 值,这是一个单独的字段(不是 object_id 字段)
在我的数据库中,我有 2 个文档 - 1 个标记为已删除,1 个标记为未删除。此代码始终返回两个文档,尽管预期结果是它仅返回未删除的文档的 Id。什么可能导致它失败?
编辑:完整示例
我的 golang 代码:
Folder.go
package main
type Folder struct {
Id int
Name string
Must bool
}
Mail.go
package main
type Mail struct{
Id int
IsDeleted bool
FoldersIds []int
Subject string
Body string
}
main.go
package main
import (
"fmt"
"github.com/globalsign/mgo"
"github.com/globalsign/mgo/bson"
)
func main(){
inbox := Folder{
Id:1,
Name:"inbox",
Must:true,
}
outbox := Folder{
Id:2,
Name:"outbox",
Must:true,
}
drafts := Folder{
Id:3,
Name:"drafts",
Must:true,
}
trash := Folder{
Id:4,
Name:"trash",
Must:true,
}
session, _ := mgo.Dial("localhost:27017")
session.DB("Outlook").C("Folders").Upsert(bson.M{"id": inbox.Id}, inbox)
session.DB("Outlook").C("Folders").Upsert(bson.M{"id": outbox.Id}, outbox)
session.DB("Outlook").C("Folders").Upsert(bson.M{"id": drafts.Id}, drafts)
session.DB("Outlook").C("Folders").Upsert(bson.M{"id": trash.Id}, trash)
mail1 := Mail{Id:1,Body:"Hello this is mail 1", FoldersIds:[]int{1}, IsDeleted:true, Subject:"Hello1"}
mail2 := Mail{Id:2,Body:"Hello this is mail 2", FoldersIds:[]int{1}, IsDeleted:false, Subject:"Hello2"}
session.DB("Outlook").C("Mails").Upsert(bson.M{"id": 1}, mail1)
session.DB("Outlook").C("Mails").Upsert(bson.M{"id": 2}, mail2)
var mails []Mail
session.DB("Outlook").C("Mails").Find(bson.M{"IsDeleted": bson.M{"$ne": true}}).Select(bson.M{"Id": 1}).All(&mails)
fmt.Println(len(mails)) // Why is this 2 and not 1?????
}
【问题讨论】:
-
请在 MongoDB 中发布您的文档。
db.mails.find()的输出。 -
@icza 我在这里做了一个简单的例子,希望它包含所有需要的细节