使用 Google Functions & Node JS 10 复制整个源文件夹而不仅仅是触发器文件

Question

需要调整以下代码，使其复制整个 sourceFolder 而不仅仅是事件文件本身，但不确定如何执行此操作。

const {Storage} = require('@google-cloud/storage');
const {path} = require('path');

exports.copyRenders = (event, context) => {
    const gcsEvent = event;
    const sourcePathOnly = gcsEvent.name



    const folderToWatch = ' ... folder on source bucket... '


// Process only if it's in the correct folder
  if (sourcePathOnly.indexOf(folderToWatch) > -1) {

    const storage = new Storage();
    const sourceFileBucket = gcsEvent.bucket
    const sourceFolder = sourcePathOnly.split('/').slice(-2) 
    const destFileBucket = 'trans-test'

    storage
    .bucket(sourceFileBucket)
    .file(sourcePathOnly)
    .copy(storage.bucket(destFileBucket).file(sourceFolder[0] + '/' + 
    sourceFolder[1])); 
  }
  console.log(`Processing file: ${sourcePathOnly}`);  
}

使用下面答案中的新代码：

const {Storage} = require('@google-cloud/storage');
const {path} = require('path');

exports.copyRenders = (event, context) => {
    const gcsEvent = event;
    const sourcePathOnly = gcsEvent.name



    const folderToWatch = ' ... folder on source bucket... '


// Process only if it's in the correct folder
  if (sourcePathOnly.indexOf(folderToWatch) > -1) {

    const storage = new Storage();
    const sourceFileBucket = gcsEvent.bucket
    const sourceFolder = sourcePathOnly.split('/').slice(-2) 
    const destFileBucket = 'trans-test'

    const options = {
        // Get the source path without the file name)
        prefix: sourcePathOnly.slice(0,sourcePathOnly.lastIndexOf("/")),
    };

    const [files] = storage.bucket(sourceFileBucket).getFiles(options);

    files.forEach(file => {
        file.copy(storage.bucket(destFileBucket).file(sourceFolder[0] + '/' + sourceFolder[1]));
        });
    }
    console.log(`Processing file: ${sourcePathOnly}`);  
}

Answer 1

您可以调用getFiles() 在您的目录中建立一个文件列表，然后复制这些文件。像这样的东西（您可能需要针对您的场景进行修改）：

const [ files ] = await storage.bucket(sourceFileBucket).getFiles({
  autoPaginate: false,
  prefix: sourceFolder
});

files.forEach(file => file.copy( ... ));

Answer 2

可以复制一个目录前缀的所有文件

const options = {
    // Get the source path without the file name)
    prefix: sourcePathOnly.slice(0,sourcePathOnly.lastIndexOf("/")),
  };

const [files] = storage.bucket(sourceFileBucket).getFiles(options);

files.forEach(file => {
    file.copy(storage.bucket(destFileBucket).file(sourceFolder[0] + '/' + 
    sourceFolder[1]));
});

请注意，每次触发您的函数时，都会复制整个前缀匹配项。如果你在同一个桶中复制，你可以创建一个指数无限循环！

注意：从数学上讲，我不知道无限的东西是否可以是指数的！