当所有其他字段值都重复时，合并两个不同的字段值

Question

当重复选择中的其他值时，我尝试组合两个小区。我试图组合的字段永远不会相同是选择中的最后一个。

SELECT field1,field2,field3,field4,field5,field6,table2.name FROM table1 INNER JOIN table2 ON table1.id = table2.table1_id INNER JOIN table2 ON table2.field8 = table2.id WHERE table1.id IN (SELECT table1_id FROM table2_table1 WHERE field8 IN (SELECT field8 FROM table3 WHERE field9 IN (1234))) AND table1.disabled = 0 AND table2.id IN (SELECT field8 FROM table3 WHERE field9 IN (1234))

所以基本上，当字段 1-6 相同并且最后一个字段有多个值时，记录只显示一行，最后一个字段结合了两个 varchar 值。

当前输出是这样的：

商店名称 1 1 main street Portland OR 97216 ROUTE-AB

商店名称 1 1 main street Portland OR 97216 ROUTE-BC

我想要这个：

商店名称 1 1 main street Portland OR 97216 ROUTE-AB,ROUTE-BC

注意：内部连接中的某些逻辑可能会关闭，因为我正在使用实时数据库并且只是尝试用通用名称替换名称。

Answer 1

这是你要找的吗？

select field1,field2,field3,field4,field5,field6,max(table2.name)+' '+ case when max(table2.name)=min(table2.name) then '' else min(table2.name) end name

from table1 INNER JOIN table2 ON table1.id = table2.table1_id 
INNER JOIN table2 ON table2.field8 = table2.id 

where table1.id in (select table1_id from table2_table1 where field8 in (select field8 from table3 where field9 in (1234))) and table1.disabled=0 and table2.id in (select field8 from table3 where field9 in (1234))
group by field1,field2,field3,field4,field5,field6