具有列和行总计的 SQL 数据透视表

Question

我正在尝试将行和列总计添加到此数据透视表中

      create table test4(city nvarchar(10), race nvarchar(30), sex nvarchar(10), age int)
            insert into test4 values ('Austin',  'African-American', 'male', 21)
            insert into test4 values ('Austin',  'Asian', 'female', 22)
            insert into test4 values ('Austin',  'Caucasian', 'male', 23)
            insert into test4 values ('Austin',  'Hispanic', 'female', 24)
            insert into test4 values ('Austin',  'African-American', 'Unknown', 25)
            insert into test4 values ('Austin',  'Asian', 'male', 26)
            insert into test4 values ('Austin',  'Caucasian', 'female', 27)
            insert into test4 values ('Austin',  'Hispanic', 'Unknown', 28)
            insert into test4 values ('Austin',  'Asian', 'male', 29)
            insert into test4 values ('Austin',  'Caucasian', 'female', 31)
            insert into test4 values ('Dallas',  'Hispanic', 'Unknown', 32)
            insert into test4 values ('Dallas',  'African-American', 'male', 33)
            insert into test4 values ('Dallas',  'Asian', 'female', 34)
            insert into test4 values ('Dallas',  'Caucasian', 'Unknown', 35)
            insert into test4 values ('Dallas',  'Hispanic', 'male', 500)
            insert into test4 values ('Dallas',  'African-American', 'female', 36)
            insert into test4 values ('Dallas',  'Asian', 'Unknown', 37)
            insert into test4 values ('Dallas',  'Caucasian', 'male', 38)
            insert into test4 values ('Dallas',  'Hispanic', 'female', 39)
            insert into test4 values ('Dallas',  'African-American', 'Unknown', 41)
            insert into test4 values ('Houston',  'Asian', 'male', 42)
            insert into test4 values ('Houston',  'Caucasian', 'female', 43)
            insert into test4 values ('Houston',  'Hispanic', 'Unknown', 44)
            insert into test4 values ('Houston',  'African-American', 'male', 45)
            insert into test4 values ('Houston',  'Asian', 'female', 46)
            insert into test4 values ('Houston',  'Caucasian', 'Unknown', 47)
            insert into test4 values ('Houston',  'Hispanic', 'male', 48)
            insert into test4 values ('Houston',  'African-American', 'female', 49)
            insert into test4 values ('Houston',  'Asian', 'Unknown', 51)
            insert into test4 values ('Houston',  'Caucasian', 'male', 52);

            WITH T AS (
            SELECT 
                  A.city as city, A.sex as sex,  
                  CASE
                        WHEN A.age BETWEEN 20 AND 30 THEN '20-30_' + race
                        WHEN A.age BETWEEN 31 AND 40 THEN '31-40_' + race
                        WHEN A.age BETWEEN 41 AND 50 THEN '41-50_' + race
                   END AS age_range_race
           FROM test4 AS A
           )
           SELECT  *
           FROM T
           PIVOT( COUNT(age_range_race) FOR age_range_race
               IN(
                  [20-30_African-American], 
                  [20-30_Asian], 
                  [20-30_Caucasian], 
                  [20-30_Hispanic],
                  [31-40_African-American], 
                  [31-40_Asian], 
                  [31-40_Caucasian], 
                  [31-40_Hispanic],
                  [41-50_African-American], 
                  [41-50_Asian], 
                  [41-50_Caucasian], 
                  [41-50_Hispanic]
                 )
            ) AS P

我正在努力实现这个结果

我可以在 Google 上找到的唯一示例是为 SQL 2000 编写的存储过程。请帮助！提前致谢

Answer 1

你试试看。

WITH T AS (
            SELECT 
                  A.city as city, A.sex as sex,  
                  CASE
                        WHEN A.age BETWEEN 20 AND 30 THEN '20-30_' + race
                        WHEN A.age BETWEEN 31 AND 40 THEN '31-40_' + race
                        WHEN A.age BETWEEN 41 AND 50 THEN '41-50_' + race
                   END AS age_range_race
           FROM #test4 AS A
           )


SELECT  *, ([20-30_African-American] + [20-30_Asian] + [20-30_Caucasian]+ [20-30_Hispanic]+ [31-40_African-American]+ [31-40_Asian]+ [31-40_Caucasian]+ [31-40_Hispanic]+[41-50_African-American]+ [41-50_Asian]+ [41-50_Caucasian]+ [41-50_Hispanic]) Total
into #tmp_result
FROM T
PIVOT( COUNT(age_range_race) FOR age_range_race
   IN(
      [20-30_African-American], 
      [20-30_Asian], 
      [20-30_Caucasian], 
      [20-30_Hispanic],
      [31-40_African-American], 
      [31-40_Asian], 
      [31-40_Caucasian], 
      [31-40_Hispanic],
      [41-50_African-American], 
      [41-50_Asian], 
      [41-50_Caucasian], 
      [41-50_Hispanic]
     )
) AS P

select * 
from #tmp_result
union all
select 'Grand Total','',SUM([20-30_African-American]), SUM([20-30_Asian]), SUM([20-30_Caucasian]), SUM([20-30_Hispanic]),SUM([31-40_African-American]), SUM([31-40_Asian]), SUM([31-40_Caucasian]), SUM([31-40_Hispanic]),SUM([41-50_African-American]), SUM([41-50_Asian]), SUM([41-50_Caucasian]),SUM([41-50_Hispanic]), sum(Total)
from #tmp_result

Answer 2

请按照以下方法尝试..

WITH T AS (
            SELECT 
                  A.city as city, A.sex as sex,  
                  CASE
                        WHEN A.age BETWEEN 20 AND 30 THEN '20-30_' + race
                        WHEN A.age BETWEEN 31 AND 40 THEN '31-40_' + race
                        WHEN A.age BETWEEN 41 AND 50 THEN '41-50_' + race
                   END AS age_range_race
           FROM #test4 AS A
           )


SELECT  *, ([20-30_African-American] + [20-30_Asian] + [20-30_Caucasian]+ [20-30_Hispanic]+ [31-40_African-American]+ [31-40_Asian]+ [31-40_Caucasian]+ [31-40_Hispanic]+[41-50_African-American]+ [41-50_Asian]+ [41-50_Caucasian]+ [41-50_Hispanic]) Total
FROM T
PIVOT( COUNT(age_range_race) FOR age_range_race
   IN(
      [20-30_African-American], 
      [20-30_Asian], 
      [20-30_Caucasian], 
      [20-30_Hispanic],
      [31-40_African-American], 
      [31-40_Asian], 
      [31-40_Caucasian], 
      [31-40_Hispanic],
      [41-50_African-American], 
      [41-50_Asian], 
      [41-50_Caucasian], 
      [41-50_Hispanic]
     )
) AS P