SQL Server 行到多列

Question

我有以下表格和数据：

CREATE TABLE SourceTbl ([Code] varchar(3), [Total] decimal, [Date] datetime );

INSERT INTO SourceTbl ([Code], [Total], [Date]) 
VALUES ('AA', 100, '2012-12-01'), ('AA', 200, '2013-02-01'), ('BB', 50, '2012-01-01');

一个简单的选择就会返回

Code | Total | Date
'AA' | 100   | 2012-12-01
'AA' | 200   | 2013-02-01
'BB' | 50    | 2012-01-01

但我需要的是以下内容

Code | Total | Date       | Total | Date
'AA  | 200   | 2013-02-01 | 100   | 2012-12-01
'BB  | 50    | 2012-01-01 | null  | null

我一直在尝试使用 PIVOT 运算符执行此操作，但没有成功（基于问题 SQL Server Pivot multiple columns based on one column）。

使用该示例，我得到的只是两行空值。

Total/Date 列可以重复 13 次，并且必须按 Date DESC 排序。

SQL 小提琴：http://sqlfiddle.com/#!3/f37a1/2

感谢任何帮助！ 谢谢！

Answer 1

如果您只需要两列：

with cte as (
    select *, row_number() over(partition by Code order by Date) as rn
    from SourceTbl
)
select
    code,
    max(case when rn = 1 then Total end) as Total1,
    max(case when rn = 1 then Date end) as Date1,
    max(case when rn = 2 then Total end) as Total2,
    max(case when rn = 2 then Date end) as Date2
from cte
group by code

=> sql fiddle demo

动态解决方案：

declare @stmt nvarchar(max)

;with cte as (
     select distinct
         cast(row_number() over(partition by Code order by Date) as nvarchar(max)) as rn
     from SourceTbl
)
select @stmt = isnull(@stmt + ', ', '') + 
    'max(case when rn = ' + rn + ' then Total end) as Total' + rn + ',' +
    'max(case when rn = ' + rn + ' then Date end) as Date' + rn 
from cte
order by rn

select @stmt = '
    with cte as (
        select *, row_number() over(partition by Code order by Date) as rn
        from SourceTbl
    )
    select
        code, ' + @stmt + ' from cte group by code'

exec sp_executesql
    @stmt = @stmt

=> sql fiddle demo

Answer 2

您是否尝试在结果集中动态创建列？

如果您有第三条记录“AA”，总数为 300，日期为 2013 年 3 月 1 日，您是否意味着您希望显示这样的内容？

Code | Total | Date       | Total | Date      | Total | Date
 AA  | 200   | 2013-02-01 | 100   | 2012-12-01| 300   | 03-01-13
 BB  | 50    | 2012-01-01 | null  | null      | null  | null