【问题标题】:converting rows to column for a set of ids将一组 id 的行转换为列
【发布时间】:2019-10-09 22:46:00
【问题描述】:

考虑以下查询:

DECLARE @t1 TABLE(
    CompanyId INT, 
    DirectorName VARCHAR(100));

INSERT INTO @t1
   VALUES
      (1,'D11'),
      (1,'D12'),
      (1,'D13'),
      (1,'D14'),
      (1,'D15'),
      (1,'D16'),
      (2,'D21'),
      (2,'D22'),
      (2,'D23'),
      (2,'D24'),
      (2,'D25'),
      (2,'D26'),
      (2,'D27'),
      (2,'D28'),
      (2,'D29'),
      (2,'D210'),
      (3,'D31'),
      (3,'D32'),
      (3,'D33');

SELECT * FROM @t1 

它只是返回 companyId 和该 ID 的一组董事。如何生成以下输出:

 CompanyId | Director1| Director2| Director3|Director4| Director5| Director6| Director7| Director8| Director9| Director10|
-----------------------------------------------------------------------------------------------------------------------------
       1           D11        D12       D13       D14        D15         D16       NULL        NULL       NULL      NULL
       2           D21        D22       D23       D24        D25         D26       D27         D28        D29       D210 
       3           D31        D32       D33       NULL       NULL        NULL      NULL        NULL       NULL      NULL 

上述查询技巧的原因在于每家公司的董事人数不同。在上面的示例中,第 2 行的导向器数量最多,这意味着最终输出中其他 id 的相关列将为空。如何创建上述输出。

为了清楚起见,在本例中,每个 id (companyId) 的结果不会超过 10 列(directors)。

【问题讨论】:

  • SQL 查询返回固定数量的列。如果您想要可变数量的列,则需要使用动态 SQL。
  • 在这个粒子问题中,我确信结果不会超过最大数量 10。所以我肯定知道最大值是多少。
  • @Gordon - 太多人在尝试调整
  • 选出前10名导演的逻辑是什么?
  • 逻辑是不同的 (DirectorName) 对于每个 Id 含义对于每个 Id 我希望将不同的导演名称视为列

标签: sql sql-server tsql sql-server-2014 sql-server-2016


【解决方案1】:

您可以通过PIVOT 使用以下解决方案:

SELECT CompanyId, [Director1], [Director2], [Director3], [Director4], [Director5], [Director6], [Director7], [Director8], [Director9], [Director10] 
FROM (
  SELECT CompanyId, DirectorName, 'Director' + CAST(ROW_NUMBER () OVER (PARTITION BY CompanyId ORDER BY CompanyId, DirectorName) AS VARCHAR(2)) AS column_name 
  FROM @t1
) st PIVOT (
  MIN(DirectorName) 
  FOR column_name IN ([Director1], [Director2], [Director3], [Director4], [Director5], [Director6], [Director7], [Director8], [Director9], [Director10])
) pt

demo on dbfiddle.uk

【讨论】:

    【解决方案2】:

    通过使用CTEROW_NUMBER 和条件聚合,您可以做到这一点

    只要每家公司的董事人数不超过10人

    ;with cteGetDirectorNum
    AS(
        select
             T.CompanyId
            ,T.DirectorName
            ,DirectorNum    ='Director'+CONVERT(VARCHAR(10), Row_Number()over( partition by T.CompanyId order by T.CompanyId, T.DirectorName))
        from
            @t1     T
    )
    SELECT
         N.CompanyId
        ,Director1      = MAX(CASE WHEN N.DirectorNum = 'Director1' THEN n.DirectorName ELSE NULL END)
        ,Director2      = MAX(CASE WHEN N.DirectorNum = 'Director2' THEN n.DirectorName ELSE NULL END)
        ,Director3      = MAX(CASE WHEN N.DirectorNum = 'Director3' THEN n.DirectorName ELSE NULL END)
        ,Director4      = MAX(CASE WHEN N.DirectorNum = 'Director4' THEN n.DirectorName ELSE NULL END)
        ,Director5      = MAX(CASE WHEN N.DirectorNum = 'Director5' THEN n.DirectorName ELSE NULL END)
        ,Director6      = MAX(CASE WHEN N.DirectorNum = 'Director6' THEN n.DirectorName ELSE NULL END)
        ,Director7      = MAX(CASE WHEN N.DirectorNum = 'Director7' THEN n.DirectorName ELSE NULL END)
        ,Director8      = MAX(CASE WHEN N.DirectorNum = 'Director8' THEN n.DirectorName ELSE NULL END)
        ,Director9      = MAX(CASE WHEN N.DirectorNum = 'Director9' THEN n.DirectorName ELSE NULL END)
        ,Director10     = MAX(CASE WHEN N.DirectorNum = 'Director10' THEN n.DirectorName ELSE NULL END)
    FROM
        cteGetDirectorNum N
    GROUP BY N.CompanyId
    

    【讨论】:

      猜你喜欢
      • 1970-01-01
      • 1970-01-01
      • 2021-09-22
      • 2012-08-04
      • 1970-01-01
      • 1970-01-01
      • 1970-01-01
      • 2023-03-14
      • 2020-02-16
      相关资源
      最近更新 更多