尝试使用多个选择语句创建表答案

【问题标题】：Trying to create a table with multiple select statements尝试使用多个选择语句创建表
【发布时间】：2021-09-17 08:06:50
【问题描述】：

这是两个 select 语句的示例，它们提取了我需要但本质上需要合并的信息，以便可以将其作为一个表读取。

SELECT  
    DATEPART(hour,start_tran_time),  
    sum(tran_qty) as 'Units Sorted'  
    FROM t_tran_log with(nolock)  
    WHERE tran_type = '311'  
    and cast(start_tran_date as date)='2021-07-03'  
    group by DATEPART(hour,start_tran_time)  
    order by DATEPART(hour,start_tran_time)

SELECT  
    DATEPART(hour,start_tran_time),  
    sum(tran_qty) as 'Total Picked'  
    FROM t_tran_log with(nolock)  
    WHERE tran_type = '301'  
    and cast(start_tran_date as date)='2021-07-03'  
    group by DATEPART(hour,start_tran_time)  
    order by DATEPART(hour,start_tran_time)

任何帮助将不胜感激。

【问题讨论】：

TSQL 危险：union all 是什么？

标签： sql tsql sql-server-2016

【解决方案1】：

如果您想按顺序插入两个查询的结果

SELECT
DATEPART(hour,start_tran_time),
sum(tran_qty) as 'Units Sorted'
FROM t_tran_log with(nolock)
WHERE tran_type = '311'
and cast(start_tran_date as date)='2021-07-03'
group by DATEPART(hour,start_tran_time)

union all
SELECT
DATEPART(hour,start_tran_time),
sum(tran_qty) as 'Total Picked'
FROM t_tran_log with(nolock)
WHERE tran_type = '301'
and cast(start_tran_date as date)='2021-07-03'
group by DATEPART(hour,start_tran_time)

如果需要订购，那么：

select * from 
   (
        SELECT
        DATEPART(hour,start_tran_time)start_tran_hour,
        sum(tran_qty) as 'Units Sorted'
        FROM t_tran_log with(nolock)
        WHERE tran_type = '311'
        and cast(start_tran_date as date)='2021-07-03'
        group by DATEPART(hour,start_tran_time)
    
        union all
        SELECT
        DATEPART(hour,start_tran_time)start_tran_hour,
        sum(tran_qty) as 'Total Picked'
        FROM t_tran_log with(nolock)
        WHERE tran_type = '301'
        and cast(start_tran_date as date)='2021-07-03'
        group by DATEPART(hour,start_tran_time)
    )t order by start_tran_hour

如果您想将两个查询的结果并排放置，则可以合并两个查询的结果：

    select A.start_tran_hour,[Units Sorted],[Total Picked]
    from
    (
        SELECT
        DATEPART(hour,start_tran_time)start_tran_hour,
        sum(tran_qty) as [Units Sorted]
        FROM t_tran_log with(nolock)
        WHERE tran_type = '311'
        and cast(start_tran_date as date)='2021-07-03'
        group by DATEPART(hour,start_tran_time)
    )A
    inner join        
    (
        SELECT
        DATEPART(hour,start_tran_time)start_tran_hour,
        sum(tran_qty) as [Total Picked]
        FROM t_tran_log with(nolock)
        WHERE tran_type = '301'
        and cast(start_tran_date as date)='2021-07-03'
        group by DATEPART(hour,start_tran_time)
    )B
    on A.start_tran_hour=B.start_tran_hour
    order by A.start_tran_hour

【讨论】：

我确实尝试过 union 和刚刚 union all 但它在运行 Msg 156, Level 15, State 1, Line 9 关键字'union'附近的语法错误。
只需删除 order by 子句。
在合并数据方面做到了这一点，唯一的问题是它将两个数据集放在一列 Units Sorted 而不是 Units Sorted 和 Total Picked。
由于某种原因，这是 0 Units Sorted Total Picked 列之一的结果。它将 Units Sorted Total Picked 放在数据部分而不是列名中。
能否分享一些示例数据！