sql server 2008 R2中如何根据空格将数据移动到下一行答案

【问题标题】：How to move the data to the next line based on spaces in sqlserver 2008 R2sql server 2008 R2中如何根据空格将数据移动到下一行
【发布时间】：2017-12-07 06:44:26
【问题描述】：

输入：如果单词到单词的空间是3个空格并且单词的长度是>9，则将列值保留到下一行。

declare @Table table(CL1 varchar(50))
    INSERT INTO @Table
    SELECT 'Ohh   my GOD'
    UNION ALL
    SELECT 'hindunewspaer is no1 paper'

select * from @Table

o/p：

CL1

ohh
my god
hindunewpaer
is no1 paper

【问题讨论】：

标签： tsql sql-server-2012 sql-server-2008-r2

【解决方案1】：

使用了拆分/解析功能。如果需要，可以内联。

EDIT - 切换到不限于 8K 的 Parser，因为最终字符串很容易大于 8K

示例

;with cte0 as (
        Select Seq=Row_Number() over (Order by (Select null)),RetSeq,RetVal
         From  @Table A
         Cross Apply ( 
                      Select RetSeq
                            ,RetVal=case when len(RetVal)>9 then '~~~' else '' end+RetVal+case when len(RetVal)>9 then '~~~' else '' end
                       From  [dbo].[udf-Str-Parse](Replace(CL1,'   ','~~~ '),' ') 
                    ) B ),
      cte1 as ( Select S=Stuff((Select ' '+RetVal From  cte0 Order by Seq For XML Path ('')),1,1,'') )                   
Select CL1 = RetVal
 From  cte1 A
 Cross Apply [dbo].[udf-Str-Parse](A.S,'~~~') B
 Order By RetSeq

退货

CL1
Ohh
my GOD
hindunewspaer
is no1 paper

必要时的拆分/解析功能

CREATE FUNCTION [dbo].[udf-Str-Parse] (@String varchar(max),@Delimiter varchar(10))
Returns Table 
As
Return (  
    Select RetSeq = Row_Number() over (Order By (Select null))
          ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)')))
    From  (Select x = Cast('<x>' + replace((Select replace(@String,@Delimiter,'§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml).query('.')) as A 
    Cross Apply x.nodes('x') AS B(i)
);
--Thanks Shnugo for making this XML safe
--Select * from [dbo].[udf-Str-Parse]('Dog,Cat,House,Car',',')
--Select * from [dbo].[udf-Str-Parse]('John Cappelletti was here',' ')
--Select * from [dbo].[udf-Str-Parse]('this,is,<test>,for,< & >',',')

【讨论】：